Hoe om te ontleed met behulp van XML vba

Question

Ek werk in die VBA, en wil om te parse'n string bv.

<PointN xsi:type='typens:PointN' 
xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' 
xmlns:xs='http://www.w3.org/2001/XMLSchema'>
    <X>24.365</X>
    <Y>78.63</Y>
</PointN>

en kry die X & Y waardes in twee afsonderlike heelgetal veranderlikes.

Ek is'n newbie wanneer dit kom by die XML, want ek is vas in VB6 en VBA, as gevolg van die veld ek werk in.

Hoe doen ek dit?

Answer 1

Dit is 'n bietjie van 'n ingewikkelde vraag, maar dit lyk asof die mees direkte roete sou wees om die XML dokument of XML string via MSXML2.DOMDocument wat dan sal jou toelaat om toegang te verkry tot die XML nodusse te laai.

Jy kan meer oor MSXML2.DOMDocument vind by die volgende plekke:

• Manipulering XML-lêers met Excel VBA & Xpath
• MSXML - http://msdn.microsoft.com /en-us/library/ms763742(VS.85).aspx
• 'n oorsig van MSXML 4.0

Answer 2

Dankie vir die wenke.

Ek weet nie, of dit is die beste benadering tot die probleem of nie, maar hier is hoe ek dit om te werk. Ek verwys die Microsoft XML, v2.6 dll in my VBA, en dan die volgende kode uit, gee my die nodige waardes

  

Dim objXML As MSXML2.DOMDocument

    Set objXML = New MSXML2.DOMDocument

    If Not objXML.loadXML(strXML) Then  'strXML is the string with XML'
        Err.Raise objXML.parseError.ErrorCode, , objXML.parseError.reason
    End If

Dim point As IXMLDOMNode
Set point = objXML.firstChild

Debug.Print point.selectSingleNode("X").Text
Debug.Print point.selectSingleNode("Y").Text

Answer 3

Voeg verwysing Project-> Verwysings Microsoft XML, 6.0 en jy kan voorbeeld kode gebruik:

  

    Dim xml As String

    xml = "<root><person><name>Me </name> </person> <person> <name>No Name </name></person></root> "
    Dim oXml As MSXML2.DOMDocument60
    Set oXml = New MSXML2.DOMDocument60
    oXml.loadXML xml
    Dim oSeqNodes, oSeqNode As IXMLDOMNode

    Set oSeqNodes = oXml.selectNodes("//root/person")
    If oSeqNodes.length = 0 Then
       'show some message
    Else
        For Each oSeqNode In oSeqNodes
             Debug.Print oSeqNode.selectSingleNode("name").Text
        Next
    End If 

versigtig wees met xml node // Root / persoon is nie dieselfde met // wortel / persoon, ook selectSingleNode ( "Naam"). Teks is nie dieselfde met selectSingleNode ( "naam"). Teks

Answer 4

Jy kan 'n XPath Query gebruik:

  

Dim objDom As Object        '// DOMDocument
Dim xmlStr As String, _
    xPath As String

xmlStr = _
    "<PointN xsi:type='typens:PointN' " & _
    "xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' " & _
    "xmlns:xs='http://www.w3.org/2001/XMLSchema'> " & _
    "    <X>24.365</X> " & _
    "    <Y>78.63</Y> " & _
    "</PointN>"

Set objDom = CreateObject("Msxml2.DOMDocument.3.0")     '// Using MSXML 3.0

'/* Load XML */
objDom.LoadXML xmlStr

'/*
' * XPath Query
' */        

'/* Get X */
xPath = "/PointN/X"
Debug.Print objDom.SelectSingleNode(xPath).text

'/* Get Y */
xPath = "/PointN/Y"
Debug.Print objDom.SelectSingleNode(xPath).text

Answer 5

Hierdie is'n voorbeeld OPML-parser werk met FeedDemon opml-lêers:

Sub debugPrintOPML()

' http://msdn.microsoft.com/en-us/library/ms763720(v=VS.85).aspx
' http://msdn.microsoft.com/en-us/library/system.xml.xmlnode.selectnodes.aspx
' http://msdn.microsoft.com/en-us/library/ms256086(v=VS.85).aspx ' expressions
' References: Microsoft XML

Dim xmldoc As New DOMDocument60
Dim oNodeList As IXMLDOMSelection
Dim oNodeList2 As IXMLDOMSelection
Dim curNode As IXMLDOMNode
Dim n As Long, n2 As Long, x As Long

Dim strXPathQuery As String
Dim attrLength As Byte
Dim FilePath As String

FilePath = "rss.opml"

xmldoc.Load CurrentProject.Path & "\" & FilePath

strXPathQuery = "opml/body/outline"
Set oNodeList = xmldoc.selectNodes(strXPathQuery)

For n = 0 To (oNodeList.length - 1)
    Set curNode = oNodeList.Item(n)
    attrLength = curNode.Attributes.length
    If attrLength > 1 Then ' or 2 or 3
        Call processNode(curNode)
    Else
        Call processNode(curNode)
        strXPathQuery = "opml/body/outline[position() = " & n + 1 & "]/outline"
        Set oNodeList2 = xmldoc.selectNodes(strXPathQuery)
        For n2 = 0 To (oNodeList2.length - 1)
            Set curNode = oNodeList2.Item(n2)
            Call processNode(curNode)
        Next
    End If
        Debug.Print "----------------------"
Next

Set xmldoc = Nothing

End Sub

Sub processNode(curNode As IXMLDOMNode)

Dim sAttrName As String
Dim sAttrValue As String
Dim attrLength As Byte
Dim x As Long

attrLength = curNode.Attributes.length

For x = 0 To (attrLength - 1)
    sAttrName = curNode.Attributes.Item(x).nodeName
    sAttrValue = curNode.Attributes.Item(x).nodeValue
    Debug.Print sAttrName & " = " & sAttrValue
Next
    Debug.Print "-----------"

End Sub

Hierdie een neem multi-bome van dopgehou (Awasu, NewzCrawler):

...
Call xmldocOpen4
Call debugPrintOPML4(Null)
...

Dim sText4 As String

Sub debugPrintOPML4(strXPathQuery As Variant)

Dim xmldoc4 As New DOMDocument60
'Dim xmldoc4 As New MSXML2.DOMDocument60 ' ?
Dim oNodeList As IXMLDOMSelection
Dim curNode As IXMLDOMNode
Dim n4 As Long

If IsNull(strXPathQuery) Then strXPathQuery = "opml/body/outline"

' http://msdn.microsoft.com/en-us/library/ms754585(v=VS.85).aspx
xmldoc4.async = False
xmldoc4.loadXML sText4
If (xmldoc4.parseError.errorCode <> 0) Then
   Dim myErr
   Set myErr = xmldoc4.parseError
   MsgBox ("You have error " & myErr.reason)
Else
'   MsgBox xmldoc4.xml
End If

Set oNodeList = xmldoc4.selectNodes(strXPathQuery)

For n4 = 0 To (oNodeList.length - 1)
    Set curNode = oNodeList.Item(n4)
    Call processNode4(strXPathQuery, curNode, n4)
Next

Set xmldoc4 = Nothing

End Sub

Sub processNode4(strXPathQuery As Variant, curNode As IXMLDOMNode, n4 As Long)

Dim sAttrName As String
Dim sAttrValue As String
Dim x As Long

For x = 0 To (curNode.Attributes.length - 1)
    sAttrName = curNode.Attributes.Item(x).nodeName
    sAttrValue = curNode.Attributes.Item(x).nodeValue
    'If sAttrName = "text"
    Debug.Print strXPathQuery & " :: " & sAttrName & " = " & sAttrValue
    'End If
Next
    Debug.Print ""

If curNode.childNodes.length > 0 Then
    Call debugPrintOPML4(strXPathQuery & "[position() = " & n4 + 1 & "]/" & curNode.nodeName)
End If

End Sub

Sub xmldocOpen4()

Dim oFSO As New FileSystemObject ' Microsoft Scripting Runtime Reference
Dim oFS
Dim FilePath As String

FilePath = "rss_awasu.opml"
Set oFS = oFSO.OpenTextFile(CurrentProject.Path & "\" & FilePath)
sText4 = oFS.ReadAll
oFS.Close

End Sub

of beter:

Sub xmldocOpen4()

Dim FilePath As String

FilePath = "rss.opml"

' function ConvertUTF8File(sUTF8File):
' http://www.vbmonster.com/Uwe/Forum.aspx/vb/24947/How-to-read-UTF-8-chars-using-VBA
' loading and conversion from Utf-8 to UTF
sText8 = ConvertUTF8File(CurrentProject.Path & "\" & FilePath)

End Sub

maar ek verstaan nie, hoekom xmldoc4 moet gelaai word elke keer.

Answer 6

Hier is 'n kort sub na 'n Micro Triforma XML lêer wat data bevat vir strukturele staal vorms ontleed nie.

  

'location of triforma structural files
'c:\programdata\bentley\workspace\triforma\tf_imperial\data\us.xml

Sub ReadTriformaImperialData()
Dim txtFileName As String
Dim txtFileLine As String
Dim txtFileNumber As Long

Dim Shape As String
Shape = "w12x40"

txtFileNumber = FreeFile
txtFileName = "c:\programdata\bentley\workspace\triforma\tf_imperial\data\us.xml"

Open txtFileName For Input As #txtFileNumber

Do While Not EOF(txtFileNumber)
Line Input #txtFileNumber, txtFileLine
    If InStr(1, UCase(txtFileLine), UCase(Shape)) Then
        P1 = InStr(1, UCase(txtFileLine), "D=")
        D = Val(Mid(txtFileLine, P1 + 3))

        P2 = InStr(1, UCase(txtFileLine), "TW=")
        TW = Val(Mid(txtFileLine, P2 + 4))

        P3 = InStr(1, UCase(txtFileLine), "WIDTH=")
        W = Val(Mid(txtFileLine, P3 + 7))

        P4 = InStr(1, UCase(txtFileLine), "TF=")
        TF = Val(Mid(txtFileLine, P4 + 4))

        Close txtFileNumber
        Exit Do
    End If
Loop
End Sub

Van hier kan jy die waardes gebruik om die vorm in Micro 2d trek of doen dit in 3d en extruderen dit om 'n soliede.

Answer 7

Update

Die prosedure hieronder aangebied gee 'n voorbeeld van die ontleding van XML met VBA gebruik van die XML DOM voorwerpe. Kode is gebaseer op 'n beginners gids van die XML DOM .

  

Public Sub LoadDocument()
Dim xDoc As MSXML.DOMDocument
Set xDoc = New MSXML.DOMDocument
xDoc.validateOnParse = False
If xDoc.Load("C:\My Documents\sample.xml") Then
   ' The document loaded successfully.
   ' Now do something intersting.
   DisplayNode xDoc.childNodes, 0
Else
   ' The document failed to load.
   ' See the previous listing for error information.
End If
End Sub

Public Sub DisplayNode(ByRef Nodes As MSXML.IXMLDOMNodeList, _
   ByVal Indent As Integer)

   Dim xNode As MSXML.IXMLDOMNode
   Indent = Indent + 2

   For Each xNode In Nodes
      If xNode.nodeType = NODE_TEXT Then
         Debug.Print Space$(Indent) & xNode.parentNode.nodeName & _
            ":" & xNode.nodeValue
      End If

      If xNode.hasChildNodes Then
         DisplayNode xNode.childNodes, Indent
      End If
   Next xNode
End Sub

  

Let wel - Hierdie aanvanklike antwoord toon die eenvoudigste moontlike ding wat ek kon dink (by die tyd Ek is besig met 'n baie spesifieke probleem).   Natuurlik met behulp van die XML fasiliteite gebou in die VBA XML Dom sou wees   baie beter. Sien die updates hierbo.

Original Response

Ek weet dit is 'n baie ou post, maar ek wou my eenvoudige oplossing vir hierdie ingewikkelde vraag te deel. Hoofsaaklik wat ek gebruik basiese string funksies om toegang te verkry tot die XML-data.

Dit veronderstel jy het 'n paar xml data (in die temp veranderlike) wat reeds teruggekeer binne 'n VBA funksie. Interessant genoeg kan 'n mens ook sien hoe ek 'n skakel na 'n XML web diens aan die waarde te haal. Die bedrag wat in die beeld funksie neem ook 'n lookup waarde omdat dit Excel VBA funksie kan verkry word vanaf binne 'n sel met behulp = functionName (waarde1, waarde2) om waardes terugkeer via die web diens in 'n sigblad.

openTag = "<" & tagValue & ">"
closeTag = "< /" & tagValue & ">" 

' Locate the position of the enclosing tags
startPos = InStr(1, temp, openTag)
endPos = InStr(1, temp, closeTag)
startTagPos = InStr(startPos, temp, ">") + 1
' Parse xml for returned value
Data = Mid(temp, startTagPos, endPos - startTagPos)

Answer 8

Dit is dikwels makliker om te ontleed sonder VBA, wanneer jy nie wil hê om makros in staat te stel. Dit kan gedoen word met die vervanging van funksie. Gee jou begin en einde nodes in selle B1 en C1.

Cell A1: {your XML here}
Cell B1: <X>
Cell C1: </X>
Cell D1: =REPLACE(A1,1,FIND(A2,A1)+LEN(A2)-1,"")
Cell E1: =REPLACE(A4,FIND(A3,A4),LEN(A4)-FIND(A3,A4)+1,"")

En die resultaat lyn E1 sal jou ontleed waarde het:

Cell A1: {your XML here}
Cell B1: <X>
Cell C1: </X>
Cell D1: 24.365<X><Y>78.68</Y></PointN>
Cell E1: 24.365