Hoe om getalle te skakel tussen heksadesimaal en desimale

Question

Hoe kan jy sit tussen heksadesimale getalle en desimale getalle in C #?

Answer 1

Om te omskep van desimale te blok waardeur doen ...

string hexValue = decValue.ToString("X");

Om te omskep van blok na desimaal doen óf ...

int decValue = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber);

of

int decValue = Convert.ToInt32(hexValue, 16);

Answer 2

Hex -> desimale:

Convert.ToInt64(hexValue, 16);

Desimale -> Hex

string.format("{0:x}", decValue);

Answer 3

Dit lyk asof jy kan sê

Convert.ToInt64(value, 16)

om die desimale kry uit hexdecimal.

Die ander manier om is:

otherVar.ToString("X");

Answer 4

As jy die maksimum werkverrigting wil wanneer jy sukses van blok na desimale getal, jy kan die benadering met pre-bevolk tafel van hex-tot-desimale waardes gebruik.

Hier is die kode wat die idee illustreer. My prestasie toetse het getoon dat dit kan wees 20% -40% vinniger as Convert.ToInt32 (...):

class TableConvert
  {
      static sbyte[] unhex_table =
      { -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
       ,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
       ,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
       , 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,-1,-1,-1,-1,-1,-1
       ,-1,10,11,12,13,14,15,-1,-1,-1,-1,-1,-1,-1,-1,-1
       ,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
       ,-1,10,11,12,13,14,15,-1,-1,-1,-1,-1,-1,-1,-1,-1
       ,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1
      };

      public static int Convert(string hexNumber)
      {
          int decValue = unhex_table[(byte)hexNumber[0]];
          for (int i = 1; i < hexNumber.Length; i++)
          {
              decValue *= 16;
              decValue += unhex_table[(byte)hexNumber[i]];
          }
          return decValue;
      }
  }

Answer 5

Van Geekpedia :

// Store integer 182
int decValue = 182;

// Convert integer 182 as a hex in a string variable
string hexValue = decValue.ToString("X");

// Convert the hex string back to the number
int decAgain = int.Parse(hexValue, System.Globalization.NumberStyles.HexNumber);

Answer 6

String stringrep = myintvar.ToString("X");

int num = int.Parse("FF", System.Globalization.NumberStyles.HexNumber);

Answer 7

    static string chex(byte e)                  // Convert a byte to a string representing that byte in hexadecimal
    {
        string r = "";
        string chars = "0123456789ABCDEF";
        r += chars[e >> 4];
        return r += chars[e &= 0x0F];
    }           // Easy enough...

    static byte CRAZY_BYTE(string t, int i)     // Take a byte, if zero return zero, else throw exception (i=0 means false, i>0 means true)
    {
        if (i == 0) return 0;
        throw new Exception(t);
    }

    static byte hbyte(string e)                 // Take 2 characters: these are hex chars, convert it to a byte
    {                                           // WARNING: This code will make small children cry. Rated R.
        e = e.ToUpper(); // 
        string msg = "INVALID CHARS";           // The message that will be thrown if the hex str is invalid

        byte[] t = new byte[]                   // Gets the 2 characters and puts them in seperate entries in a byte array.
        {                                       // This will throw an exception if (e.Length != 2).
            (byte)e[CRAZY_BYTE("INVALID LENGTH", e.Length ^ 0x02)], 
            (byte)e[0x01] 
        };

        for (byte i = 0x00; i < 0x02; i++)      // Convert those [ascii] characters to [hexadecimal] characters. Error out if either character is invalid.
        {
            t[i] -= (byte)((t[i] >= 0x30) ? 0x30 : CRAZY_BYTE(msg, 0x01));                                  // Check for 0-9
            t[i] -= (byte)((!(t[i] < 0x0A)) ? (t[i] >= 0x11 ? 0x07 : CRAZY_BYTE(msg, 0x01)) : 0x00);        // Check for A-F
        }           

        return t[0x01] |= t[0x00] <<= 0x04;     // The moment of truth.
    }

Answer 8

Dit is nie regtig maklikste manier maar hierdie bron kode in staat stel om enige tipe van oktale getal regs d.w.z 23,214, 23 en 0,512 en so aan. Hoop dit sal jou help ..

    public string octal_to_decimal(string m_value)
    {
        double i, j, x = 0;
        Int64 main_value;
        int k = 0;
        bool pw = true, ch;
        int position_pt = m_value.IndexOf(".");
        if (position_pt == -1)
        {
            main_value = Convert.ToInt64(m_value);
            ch = false;
        }
        else
        {
            main_value = Convert.ToInt64(m_value.Remove(position_pt, m_value.Length - position_pt));
            ch = true;
        }

        while (k <= 1)
        {
            do
            {
                i = main_value % 10;                                        // Return Remainder
                i = i * Convert.ToDouble(Math.Pow(8, x));                   // calculate power
                if (pw)
                    x++;
                else
                    x--;
                o_to_d = o_to_d + i;                                        // Saving Required calculated value in main variable
                main_value = main_value / 10;                               // Dividing the main value 
            }
            while (main_value >= 1);
            if (ch)
            {
                k++;
                main_value = Convert.ToInt64(Reversestring(m_value.Remove(0, position_pt + 1)));
            }
            else
                k = 2;
            pw = false;
            x = -1;
        }
        return (Convert.ToString(o_to_d));
    }    

Answer 9

Hex om Desimale Gesprek

Convert.ToInt32(number, 16);

Desimale te Hex Gesprek

int.Parse(number, System.Globalization.NumberStyles.HexNumber)

Vir meer besonderhede Bevestig hierdie artikel

Answer 10

Probeer BigNumber in C # -. Verteenwoordig 'n arbitrêr groot onderteken heelgetal

Program

using System.Numerics;
...
var bigNumber = BigInteger.Parse("837593454735734579347547357233757342857087879423437472347757234945743");
Console.WriteLine(bigNumber.ToString("X"));

Uitgawe

4F30DC39A5B10A824134D5B18EEA3707AC854EE565414ED2E498DCFDE1A15DA5FEB6074AE248458435BD417F06F674EB29A2CFECF

moontlike uitsonderings,

ArgumentNullException -. N waarde is null

FormatException - waarde is nie in die regte formaat

.

Gevolgtrekking

Jy kan string omskep en slaan 'n waarde in BigNumber sonder beperkings oor die grootte van die getal tensy die string is leeg en nie-analphabets

Answer 11

Hier is my funksie:

using System;
using System.Collections.Generic;
class HexadecimalToDecimal
{
    static Dictionary<char, int> hexdecval = new Dictionary<char, int>{
        {'0', 0},
        {'1', 1},
        {'2', 2},
        {'3', 3},
        {'4', 4},
        {'5', 5},
        {'6', 6},
        {'7', 7},
        {'8', 8},
        {'9', 9},
        {'a', 10},
        {'b', 11},
        {'c', 12},
        {'d', 13},
        {'e', 14},
        {'f', 15},
    };

    static decimal HexToDec(string hex)
    {
        decimal result = 0;
        hex = hex.ToLower();

        for (int i = 0; i < hex.Length; i++)
        {
            char valAt = hex[hex.Length - 1 - i];
            result += hexdecval[valAt] * (int)Math.Pow(16, i);
        }

        return result;
    }

    static void Main()
    {

        Console.WriteLine("Enter Hexadecimal value");
        string hex = Console.ReadLine().Trim();

        //string hex = "29A";
        Console.WriteLine("Hex {0} is dec {1}", hex, HexToDec(hex));

        Console.ReadKey();
    }
}

Answer 12

As dit is 'n baie groot blok string buite die vermoë van die normale getal:

Vir NET 3.5, ons kan BouncyCastle se Biginteger klas gebruik:

String hex = "68c7b05d0000000002f8";
// results in "494809724602834812404472"
String decimal = new Org.BouncyCastle.Math.BigInteger(hex, 16).ToString();

NET 4.0 het die Biginteger klas.

Answer 13

My weergawe is ek dink 'n bietjie meer verstaanbaar omdat my C # kennis is nie so hoog is. Ek gebruik hierdie algoritme: http://easyguyevo.hubpages.com/hub/ omskep-Hex-tot-Desimale (Die Voorbeeld 2)

using System;
using System.Collections.Generic;

static class Tool
{
    public static string DecToHex(int x)
    {
        string result = "";

        while (x != 0)
        {
            if ((x % 16) < 10)
                result = x % 16 + result;
            else
            {
                string temp = "";

                switch (x % 16)
                {
                    case 10: temp = "A"; break;
                    case 11: temp = "B"; break;
                    case 12: temp = "C"; break;
                    case 13: temp = "D"; break;
                    case 14: temp = "E"; break;
                    case 15: temp = "F"; break;
                }

                result = temp + result;
            }

            x /= 16;
        }

        return result;
    }

    public static int HexToDec(string x)
    {
        int result = 0;
        int count = x.Length - 1;
        for (int i = 0; i < x.Length; i++)
        {
            int temp = 0;
            switch (x[i])
            {
                case 'A': temp = 10; break;
                case 'B': temp = 11; break;
                case 'C': temp = 12; break;
                case 'D': temp = 13; break;
                case 'E': temp = 14; break;
                case 'F': temp = 15; break;
                default: temp = -48 + (int)x[i]; break; // -48 because of ASCII
            }

            result += temp * (int)(Math.Pow(16, count));
            count--;
        }

        return result;
    }
}

class Program
{
    static void Main(string[] args)
    {
        Console.Write("Enter Decimal value: ");
        int decNum = int.Parse(Console.ReadLine());

        Console.WriteLine("Dec {0} is hex {1}", decNum, Tool.DecToHex(decNum));

        Console.Write("\nEnter Hexadecimal value: ");
        string hexNum = Console.ReadLine().ToUpper();

        Console.WriteLine("Hex {0} is dec {1}", hexNum, Tool.HexToDec(hexNum));

        Console.ReadKey();
    }
}

Answer 14

Skakel binêre na Hex

Convert.ToString(Convert.ToUInt32(binary1, 2), 16).ToUpper()

Answer 15

My oplossing is 'n bietjie soos terug na die basics, maar dit werk sonder die gebruik van enige ingeboude funksies om te skakel tussen getallestelsels.

    public static string DecToHex(long a)
    {
        int n = 1;
        long b = a;
        while (b > 15)
        {
            b /= 16;
            n++;
        }
        string[] t = new string[n];
        int i = 0, j = n - 1;
        do
        {
                 if (a % 16 == 10) t[i] = "A";
            else if (a % 16 == 11) t[i] = "B";
            else if (a % 16 == 12) t[i] = "C";
            else if (a % 16 == 13) t[i] = "D";
            else if (a % 16 == 14) t[i] = "E";
            else if (a % 16 == 15) t[i] = "F";
            else t[i] = (a % 16).ToString();
            a /= 16;
            i++;
        }
        while ((a * 16) > 15);
        string[] r = new string[n];
        for (i = 0; i < n; i++)
        {
            r[i] = t[j];
            j--;
        }
        string res = string.Concat(r);
        return res;
    }

Answer 16

class HexToDecimal
{
    static void Main()
    {
        while (true)
        {
            Console.Write("Enter digit number to convert: ");
            int n = int.Parse(Console.ReadLine()); // set hexadecimal digit number  
            Console.Write("Enter hexadecimal number: ");
            string str = Console.ReadLine();
            str.Reverse();

            char[] ch = str.ToCharArray();
            int[] intarray = new int[n];

            decimal decimalval = 0;

            for (int i = ch.Length - 1; i >= 0; i--)
            {
                if (ch[i] == '0')
                    intarray[i] = 0;
                if (ch[i] == '1')
                    intarray[i] = 1;
                if (ch[i] == '2')
                    intarray[i] = 2;
                if (ch[i] == '3')
                    intarray[i] = 3;
                if (ch[i] == '4')
                    intarray[i] = 4;
                if (ch[i] == '5')
                    intarray[i] = 5;
                if (ch[i] == '6')
                    intarray[i] = 6;
                if (ch[i] == '7')
                    intarray[i] = 7;
                if (ch[i] == '8')
                    intarray[i] = 8;
                if (ch[i] == '9')
                    intarray[i] = 9;
                if (ch[i] == 'A')
                    intarray[i] = 10;
                if (ch[i] == 'B')
                    intarray[i] = 11;
                if (ch[i] == 'C')
                    intarray[i] = 12;
                if (ch[i] == 'D')
                    intarray[i] = 13;
                if (ch[i] == 'E')
                    intarray[i] = 14;
                if (ch[i] == 'F')
                    intarray[i] = 15;

                decimalval += intarray[i] * (decimal)Math.Pow(16, ch.Length - 1 - i);

            }

            Console.WriteLine(decimalval);
        }

    }

}

Answer 17

'n uitbreiding metode vir die omskakeling van 'n byte array in 'n blok verteenwoordiging. Dit pads elke byte met vooraanstaande nulle.

    /// <summary>
    /// Turns the byte array into its Hex representation.
    /// </summary>
    public static string ToHex(this byte[] y)
    {
        StringBuilder sb = new StringBuilder();
        foreach (byte b in y)
        {
            sb.Append(b.ToString("X").PadLeft(2, "0"[0]));
        }
        return sb.ToString();
    }