FROM inventory_location il
LEFT JOIN item_stock iss ON iss.inv_loc_id = il.inv_loc_id
LEFT JOIN item i ON iss.item_id = i.item_id
更改您的条款,以便您从natventory_location开始。
题
我有三张桌子,inventory_location,item,item_stock
natventory_location :
inv_loc_id (PK)
inv_loc_desc
物品 :
item_id (PK)
code_no
item_desc
inv_cat_id
item_stock :
item_stock_id (PK)
item_id
inv_loc_id
quantity
我想显示这样的报告:
代码说明LOC1 LOC2总计
1 desc1 5 3 8
inventory_location有数据: (Loc1,Loc2,Loc3,Loc4,Loc5)
&可以与另一个记录一起添加。
我的问题是,如果一个位置尚未在 item_stock
- 意味着还没有存储其中的项目,它将显示如下:
代码说明LOC1 LOC2 NULL NULL总计
1 desc1 5 3 0 0 8
我需要的是,即使尚未显示所有位置 item_stock
.
这是我的查询,希望您能纠正我。
SELECT
il.`inv_loc_id` AS inv_loc_id,
il.`inv_loc_desc` AS inv_loc_desc,
i.`item_id` AS item_id,
i.`nrc_no` AS nrc_no,
i.`code_no` AS code_no,
i.`item_desc` AS item_desc,
i.`unit_id` AS unit_id,
iss.`item_stock_id` AS item_stock_id,
iss.`inv_loc_id` AS inv_loc_id,
iss.`quantity` AS quantity,
i.`inv_cat_id` AS inv_cat_id
FROM `item` i
LEFT JOIN `item_stock` iss
ON iss.`item_id` = i.`item_id`
LEFT JOIN `inventory_location` AS il
ON il.`inv_loc_id` = iss.`inv_loc_id`
WHERE i.inv_cat_id = 1
GROUP BY iss.inv_loc_id,
i.item_id
ORDER BY iss.item_stock_id DESC
解决方案
FROM inventory_location il
LEFT JOIN item_stock iss ON iss.inv_loc_id = il.inv_loc_id
LEFT JOIN item i ON iss.item_id = i.item_id
更改您的条款,以便您从natventory_location开始。