pg_search使用Assocy_against给出错误“列[model_name]。

Question

我正在尝试使用pg_search搜索关联的模型。当我运行搜索时，我会收到错误“ PG ::错误：错误：列计划。名称不存在”。我正在运行“计划”模型中的搜索，并试图用“名称”列的“地点”搜索“地点”。 has_many：通过连接它们的模型是多态性的。以某种方式，SQL查询将两者结合在一起并丢弃错误。我已经运行了Assoct_against迁移（Rails G PG_Search：Migration：Assoct_against），搜寻文档，并寻找其他错误并没有提出的其他人，一定是我只是在忽略某些东西。如果我只删除plan.rb中的iSsect_against行，它可以正确运行（没有更广泛的搜索结果）。任何帮助，将不胜感激！

plan.rb：

class Plan < ActiveRecord::Base
    belongs_to :user
    has_many :plan_places, :dependent => :destroy
    has_many :places, through: :plan_places, source: :plan

    include PgSearch
    pg_search_scope :search, :against => [:title, :summary],
        associated_against: { places: [:name, :address]},
        using: {tsearch: {dictionary: "english"}},
        ignoring: :accents

    def self.text_query(query)
        if query.present?
          search(query)
        else
          scoped
        end
    end
end

place.rb：

class Place < ActiveRecord::Base
    has_many :plan_places, as: :sortable #polymorphic -- could this be the issue??
    has_many :plans, through: :plan_places

   include PgSearch
        multisearchable :against => [:name, :address]
        pg_search_scope :search, against: [:name, :address],
            using: {tsearch: {dictionary: "english"}},
            ignoring: :accents
    def self.text_query(query)
            if query.present?
              search(query)
            else
              scoped
            end
    end
end

控制器：

def index
    query = params[:query]
    @plans = Plan.text_query(query)
  end

完整错误消息：

PG::Error: ERROR:  column plans.name does not exist
LINE 1: ...OUTER JOIN (SELECT "plans"."id" AS id, string_agg("plans"."n...
                                                             ^
: SELECT "plans".*, ((ts_rank((to_tsvector('english', unaccent(coalesce("plans"."title"::text, ''))) || to_tsvector('english', unaccent(coalesce("plans"."summary"::text, ''))) || to_tsvector('english', unaccent(coalesce(pg_search_ef8b0c36567cc241900c73.pg_search_1d546fcf34c118d2a7b8f6::text, ''))) || to_tsvector('english', unaccent(coalesce(pg_search_ef8b0c36567cc241900c73.pg_search_f3147101e01c522d780049::text, '')))), (to_tsquery('english', ''' ' || unaccent('giraffe') || ' ''')), 0))) AS pg_search_rank FROM "plans" LEFT OUTER JOIN (SELECT "plans"."id" AS id, string_agg("plans"."name"::text, ' ') AS pg_search_1d546fcf34c118d2a7b8f6, string_agg("plans"."address"::text, ' ') AS pg_search_f3147101e01c522d780049 FROM "plans" INNER JOIN "plan_places" ON "plan_places"."plan_id" = "plans"."id" INNER JOIN "plans" "places_plans" ON "places_plans"."id" = "plan_places"."plan_id" GROUP BY "plans"."id") pg_search_ef8b0c36567cc241900c73 ON pg_search_ef8b0c36567cc241900c73.id = "plans"."id" WHERE (((to_tsvector('english', unaccent(coalesce("plans"."title"::text, ''))) || to_tsvector('english', unaccent(coalesce("plans"."summary"::text, ''))) || to_tsvector('english', unaccent(coalesce(pg_search_ef8b0c36567cc241900c73.pg_search_1d546fcf34c118d2a7b8f6::text, ''))) || to_tsvector('english', unaccent(coalesce(pg_search_ef8b0c36567cc241900c73.pg_search_f3147101e01c522d780049::text, '')))) @@ (to_tsquery('english', ''' ' || unaccent('giraffe') || ' '''))))  ORDER BY pg_search_rank DESC, "plans"."id" ASC, created_at DESC

Answer 1

如果其他人遇到这种情况，我最终使用了一些有些黑客的解决方法。在计划模型的搜索方法中，我刚刚在儿童模型（位置）上运行搜索，使用has_many：通过表（plan_places）获取结果的关联计划，然后将此列表附加到常规的计划搜索结果。这很丑陋，可能非常低效，因此，如果有人知道“真正的”答案，请提交！

def self.text_query(query)
    if query.present?
      place_ids = Place.text_query(query).map(&:id).uniq
      plan_ids = PlanPlace.where(sortable_id: place_ids, sortable_type: "Place").map(&:plan_id).uniq
      plans = find(plan_ids)
      plans = plans + search(query)
    else
      scoped
    end
  end