忽略XML序列化中的空值

Question

我有一块看起来像的xml

  <SubscriptionProduct>
    <SubscriptionProductIdentifier>
      <SubscriptionProductIdentifierType>
        <SubscriptionProductIDType>01</SubscriptionProductIDType>
        <ID>123456</ID>
        <Value>AAAA</Value>
      </SubscriptionProductIdentifierType>
      <SubscriptionProductIdentifierType xsi:nil="true" />
    </SubscriptionProductIdentifier>
    <SubscriptionProductDescription />
  </SubscriptionProduct>

.

您可以看到subscriptionProductiatientifierType是一个集合，在这种情况下只包含一个项目。
如何忽略第二个空项目？

我尝试添加XML忽略，但是它删除整个集合，如果没有数据，我只希望删除集合中的第二项。

[System.Xml.Serialization.XmlIgnoreAttribute()]
public SubscriptionProductIdentifierType[] SubscriptionProductIdentifier {
    get {
        return this.subscriptionProductIdentifierField;
    }
    set {
        this.subscriptionProductIdentifierField = value;
    }
}

.

任何帮助将非常感激。

亲切的问候 zal

Answer 1

There is not one item in your collection but two, one of which is null

just filter null items during addition, or even before return, depending on your business logic

public SubscriptionProductIdentifierType[] SubscriptionProductIdentifier {
    get {
        return this.subscriptionProductIdentifierField.Where(s=>s!=null).ToArray();
    }
...
}

Hope this helps

Answer 2

XmlIgnoreAttribute will ignore the member, not just items that are null within an array. If you have no way of filtering the results or removing the null node ahead of time, then store a local variable to hold the filtered results and lazy load it.

private SubscriptionProductIdentifierType[] _subscriptionProductIdentifierField = null;
private SubscriptionProductIdentifierType[] _filteredSubscriptionProductIdentifier = null;

public SubscriptionProductIdentifierType[] SubscriptionProductIdentifier
{
    get { 
    return this._filteredSubscriptionProductIdentifier ?? (
        _filteredSubscriptionProductIdentifier = Array.FindAll(
            this._subscriptionProductIdentifierField, 
            delegate(SubscriptionProductIdentifierType t) { return t != null; } ));

}
    set
    {
        this._subscriptionProductIdentifierField = value;
        this._filteredSubscriptionProductIdentifier = null;
    }
}