题
谁能告诉我为什么num_chars和num_rows必须相同?
from ctypes import *
num_chars = 8
num_rows = 8
num_cols = 6
buffer = create_string_buffer (num_chars*num_rows*num_cols+num_chars)
for char in range(num_chars):
for row in range(num_rows):
for col in range(num_cols):
if char == num_chars-1 and col == num_cols-1:
buffer[row*num_rows*num_cols+char*num_cols+col+row] = '|'
buffer[row*num_rows*num_cols+char*num_cols+col+row+1] = '\n'
elif col == num_cols-1:
buffer[row*num_rows*num_cols+char*num_cols+col+row] = '|'
else:
buffer[row*num_rows*num_cols+char*num_cols+col+row] = ('.', '*')[char>row]
print buffer.value
输出
.....|*****|*****|*****|*****|*****|*****|*****|
.....|.....|*****|*****|*****|*****|*****|*****|
.....|.....|.....|*****|*****|*****|*****|*****|
.....|.....|.....|.....|*****|*****|*****|*****|
.....|.....|.....|.....|.....|*****|*****|*****|
.....|.....|.....|.....|.....|.....|*****|*****|
.....|.....|.....|.....|.....|.....|.....|*****|
.....|.....|.....|.....|.....|.....|.....|.....|
现在将num_chars更改为15。
.....|*****|*****|*****|*****|*****|*****|*****|*****|*****|*****|*****|*****|*****|*****|
*****|*****|*****|*****|*****|*****|*****|*****|
*****|*****|*****|*****|*****|*****|*****|*****|
*****|*****|*****|*****|*****|*****|*****|*****|
*****|*****|*****|*****|*****|*****|*****|*****|
*****|*****|*****|*****|*****|*****|*****|*****|
*****|*****|*****|*****|*****|*****|*****|*****|
.....|*****|*****|*****|*****|*****|*****|*****|
解决方案
您说您正在使用CTYPES,因为您想要可变的char缓冲区。但是您可以从列表理解中获得所需的输出
num_chars = 5
num_rows = 8
empty = ['.' * num_chars]
full = ['*' * num_chars]
print '\n'.join(
'|'.join(empty * (i + 1) + (num_rows - i - 1) * full)
for i in xrange(num_rows)
)
.....|*****|*****|*****|*****|*****|*****|*****
.....|.....|*****|*****|*****|*****|*****|*****
.....|.....|.....|*****|*****|*****|*****|*****
.....|.....|.....|.....|*****|*****|*****|*****
.....|.....|.....|.....|.....|*****|*****|*****
.....|.....|.....|.....|.....|.....|*****|*****
.....|.....|.....|.....|.....|.....|.....|*****
.....|.....|.....|.....|.....|.....|.....|.....
编辑
我将向您展示如何使用列表综合来绘制您想绘制的任何字符。这个想法很简单。在要打印角色的地方构建一个带有true的布尔数组,否则为false。并只使用“或”技巧来打印正确的字符。这个示例将建立像董事会这样的国际象棋。您可以使用相同的概念来绘制所需的任何形状。
rows = 5
cols = 6
char = '#'
empty = '.'
bitmap = [[ (i + j)%2 == 0 for i in xrange(cols)] for j in xrange(rows)]
print '\n'.join(
'|'.join(bitmap[j][i] * char or empty for i in xrange(cols))
for j in xrange(rows)
)
其他提示
我们去。我有行num_rows而不是行num_chars我必须需要一个胡椒博士。顺便说一句,这不是作业。它是用于LCD项目。
num_chars = 10
num_rows = 8
num_cols = 6
buffer = create_string_buffer (num_chars*num_rows*num_cols+num_chars)
for char in range(num_chars):
for row in range(num_rows):
for col in range(num_cols):
if char == num_chars-1 and col == num_cols-1:
buffer[row*num_chars*num_cols+char*num_cols+col+row] = '|'
buffer[row*num_chars*num_cols+char*num_cols+col+row+1] = '\n'
elif col == num_cols-1:
buffer[row*num_chars*num_cols+char*num_cols+col+row] = '|'
else:
buffer[row*num_chars*num_cols+char*num_cols+col+row] = ('.', '*')[char>row]
print repr(buffer.raw)
print buffer.value
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