R:使用均值和SD函数标准化
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11-12-2019 - |
题
我正在尝试做一个简单的转换。我使用了以下代码,它工作正常:
data_stdz <- transform(data_header, z.v1 = v1+2)
.
但是,我无法获得以下代码来工作:
data_stdz <- transform(data_header, z.v1 = (v1 - mean(v1))/(2*sd(v1))
.
我还试图只需工作的均值:
data_stdz <- transform(data_header, z.v1 = mean(v1)
.
但是,我一直在收到以下错误:
Error: unexpected symbol in:
"data_std2 <- transform(data_header, z.v1 = mean(v1)
data_std2"
.
所以我猜测它与我使用均值和SD函数有关,但我无法弄清楚。
数据示例:
v1 v2 v3
6.7 3.8 1.2
6.3 3.2 1.2
6.1 2.6 1.6
7 2.4 1
NA NA NA
6.5 3.6 2.6
6.1 2.4 1.6
6 5.6 5.2
7 2.8 1
6.7 3.8 1.4
5.7 4.2 2.6
5.1 5.6 5
NA NA NA
. 解决方案
Your problem is likely (in additon to what gavin said) the NAs. Use na.rm=TRUE
as in:
transform(data_header, z.v1 = (v1 - mean(v1, na.rm =T))/(2*sd(v1, na.rm =T)))
其他提示
Base R has the scale()
function for this purpose.
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