使用Verilog先进先出（FIFO）

Question

你好，我真的需要帮助这个，因为它让我疯狂的我疯狂的我使用spartan 3e，下面是fifo和之后的.ucf文件......我只是想知道为什么我不能写入/读到内存虽然当我生成二进制文件并编程FPGA时，我没有错误！

---

module fifo (
  input [3:0] data_in, 
  input clk, rst, rd, wr, 
  output empty, full, 
  output reg [3:0] fifo_cnt,
  output reg [3:0] data_out
); 

reg [3:0] fifo_ram[0:7];
reg [2:0] rd_ptr, wr_ptr;

assign empty = (fifo_cnt==0);
assign full = (fifo_cnt==8);

always @( posedge clk ) 
begin: write
if(wr && !full) fifo_ram[wr_ptr] <= data_in;
else if(wr && rd) fifo_ram[wr_ptr] <= data_in;
end

always @( posedge clk ) 
begin: read
if(rd && !empty)
  data_out <= fifo_ram[rd_ptr];
else if(rd && wr && empty) 
  data_out <= fifo_ram[rd_ptr];
end

always @( posedge clk ) 
begin: pointer
  if( rst ) 
  begin 
    wr_ptr <= 0; 
    rd_ptr <= 0;
  end 
  else 
  begin
    wr_ptr <= ((wr && !full)||(wr && rd)) ? wr_ptr+1 : wr_ptr;
    rd_ptr <= ((rd && !empty)||(wr && rd)) ? rd_ptr+1 : rd_ptr;
  end 
end

always @( posedge clk ) 
begin: count 
  if( rst ) 
    fifo_cnt <= 0;
  else 
  begin
    case ({wr,rd})
      2'b00 : fifo_cnt <= fifo_cnt;
      2'b01 : fifo_cnt <= (fifo_cnt==0) ? 0 : fifo_cnt-1; 
      2'b10 : fifo_cnt <= (fifo_cnt==8) ? 8 : fifo_cnt+1; 
      2'b11 : fifo_cnt <= fifo_cnt;
      default: fifo_cnt <= fifo_cnt;
    endcase 
  end
end


endmodule  

.

---

# ==== Clock Source ==== 
NET "clk" LOC = "C9" | IOSTANDARD = LVCMOS33; 
NET "clk" PERIOD = 5ns HIGH 40%; 


NET "rst"     LOC "D18" | IOSTANDARD = LVTTL | PULLDOWN ;  
NET "wr"      LOC "H13" | IOSTANDARD = LVTTL | PULLDOWN ;  
NET "rd"      LOC "K17" | IOSTANDARD = LVTTL | PULLDOWN ;


# ==== Slide Switches (SW) ==== 
NET "data_in<0>" LOC = "L13" | IOSTANDARD = LVTTL | PULLUP ; #// SW1 
NET "data_in<1>" LOC = "L14" | IOSTANDARD = LVTTL | PULLUP ; #// SW2
NET "data_in<2>" LOC = "H18" | IOSTANDARD = LVTTL | PULLUP ; #// SW3
NET "data_in<3>" LOC = "N17" | IOSTANDARD = LVTTL | PULLUP ; #// SW4


# ==== Discrete LEDs (LED) ==== 
NET "data_out<3>" LOC = "F11" | IOSTANDARD = LVTTL | SLEW = SLOW | DRIVE = 8 ;
NET "data_out<2>" LOC = "E11" | IOSTANDARD = LVTTL | SLEW = SLOW | DRIVE = 8 ;
NET "data_out<1>" LOC = "E12" | IOSTANDARD = LVTTL | SLEW = SLOW | DRIVE = 8 ;
NET "data_out<0>" LOC = "F12" | IOSTANDARD = LVTTL | SLEW = SLOW | DRIVE = 8 ; 

NET "empty"   LOC "E9" | IOSTANDARD = LVTTL | SLEW = SLOW | DRIVE = 8 ;
NET "full"    LOC "F9" | IOSTANDARD = LVTTL | SLEW = SLOW | DRIVE = 8 ;

.

Answer 1

好的，我在一个de0-nano板上尝试了它，它使用Altera Cyclone IV部分，并且能够将其工作，所以您的逻辑很好。我确实添加的一件事是RD和WR信号的边缘检测。

使用当前代码（和我的电路板）当您按下交换机时，我获得了许多连续的读数或写入。因此，单次按下WR开关将填充FIFO，单按下读取开关将清空FIFO。

我将RD输入信号重命名为RD_IN和WR信号到WR_IN并添加以下代码：

always @( posedge clk ) 
begin: edge_detect
  rd_in_d <= rd_in;
  wr_in_d <= wr_in;

  rd = (rd_in && !rd_in_d);
  wr = (wr_in && !wr_in_d);
end

.

在检测到RD_IN或WR_IN信号的上升沿时，才会为您提供单个RD / WR脉冲。

确保当您展示的开关不会按下开关时，开关信号很低。在我的电路板上，开关输入始终高（上拉电阻），并且在按下开关时才能降低。由于开关的按压创建逻辑低调，因此我必须颠倒RD / WR信号，让它们与代码正确地工作。

希望这有帮助！