如何在 VBA (Excel) 中获取以毫秒为单位的 DateDiff-Value?
题
我需要计算两个时间戳之间的差异(以毫秒为单位)。不幸的是,VBA 的 DateDiff 函数不提供这种精度。有什么解决方法吗?
解决方案
您可以使用描述此处该方法如下: -
创建名为StopWatch
一个新的类模块
把下面的代码的StopWatch
类模块中:
Private mlngStart As Long
Private Declare Function GetTickCount Lib "kernel32" () As Long
Public Sub StartTimer()
mlngStart = GetTickCount
End Sub
Public Function EndTimer() As Long
EndTimer = (GetTickCount - mlngStart)
End Function
您使用的代码,如下所示:
Dim sw as StopWatch
Set sw = New StopWatch
sw.StartTimer
' Do whatever you want to time here
Debug.Print "That took: " & sw.EndTimer & "milliseconds"
的其它方法描述使用VBA定时器功能,但是这仅是精确到秒(厘秒)的百分之一。
其他提示
如果你只需要在厘秒经过的时间,那么你不需要计时单位计数API。你可以只使用VBA.Timer方法,它存在于所有的Office产品。
Public Sub TestHarness()
Dim fTimeStart As Single
Dim fTimeEnd As Single
fTimeStart = Timer
SomeProcedure
fTimeEnd = Timer
Debug.Print Format$((fTimeEnd - fTimeStart) * 100!, "0.00 "" Centiseconds Elapsed""")
End Sub
Public Sub SomeProcedure()
Dim i As Long, r As Double
For i = 0& To 10000000
r = Rnd
Next
End Sub
的GetTickCount和性能计数器,如果你想要去的微秒所需的.. 对于millisenconds你可以用一些这样的事..
'at the bigining of the module
Private Type SYSTEMTIME
wYear As Integer
wMonth As Integer
wDayOfWeek As Integer
wDay As Integer
wHour As Integer
wMinute As Integer
wSecond As Integer
wMilliseconds As Integer
End Type
Private Declare Sub GetLocalTime Lib "kernel32" (lpSystemTime As SYSTEMTIME)
'In the Function where you need find diff
Dim sSysTime As SYSTEMTIME
Dim iStartSec As Long, iCurrentSec As Long
GetLocalTime sSysTime
iStartSec = CLng(sSysTime.wSecond) * 1000 + sSysTime.wMilliseconds
'do your stuff spending few milliseconds
GetLocalTime sSysTime ' get the new time
iCurrentSec=CLng(sSysTime.wSecond) * 1000 + sSysTime.wMilliseconds
'Different between iStartSec and iCurrentSec will give you diff in MilliSecs
您还可以使用在细胞计算=NOW()
式:
Dim ws As Worksheet
Set ws = Sheet1
ws.Range("a1").formula = "=now()"
ws.Range("a1").numberFormat = "dd/mm/yyyy h:mm:ss.000"
Application.Wait Now() + TimeSerial(0, 0, 1)
ws.Range("a2").formula = "=now()"
ws.Range("a2").numberFormat = "dd/mm/yyyy h:mm:ss.000"
ws.Range("a3").formula = "=a2-a1"
ws.Range("a3").numberFormat = "h:mm:ss.000"
var diff as double
diff = ws.Range("a3")
道歉唤醒这个老帖子,但我得到了一个答案:点击 像这样写为毫秒的函数:
Public Function TimeInMS() As String
TimeInMS = Strings.Format(Now, "HH:nn:ss") & "." & Strings.Right(Strings.Format(Timer, "#0.00"), 2)
End Function
在你的子,使用此功能:
Sub DisplayMS()
On Error Resume Next
Cancel = True
Cells(Rows.Count, 2).End(xlUp).Offset(1) = TimeInMS()
End Sub
除了 AdamRalph 描述的方法(GetTickCount()
), 你可以这样做:
- 使用
QueryPerformanceCounter()
和QueryPerformanceFrequency()
API函数
如何测试VBA代码的运行时间? - 或者,对于无法访问 Win32 API(如 VBScript)的环境,如下所示:
http://ccrp.mvps.org/ (检查“高性能定时器”可安装 COM 对象的下载部分。他们是免费的。)
不隶属于 StackOverflow