如何为SQL Server 2005实例中的所有数据库创建DDL触发器

Question

我将为 SQL Server 实例中的所有数据库创建一个 DDL 触发器。我想在一次运行中完成此操作，而不是为每个数据库运行多次。

下面是我需要执行的两个 T-SQL 语句：

-- Create table

use <dbname>
GO
CREATE TABLE dbo.ChangeAttempt
(EventData xml NOT NULL,
AttemptDate datetime NOT NULL DEFAULT GETDATE(),
DBUser char(50) NOT NULL)
GO

-- Create DDL trigger 

use <dbname>
GO
CREATE TRIGGER db_trg_ObjectChanges
ON DATABASE
FOR ALTER_PROCEDURE, DROP_PROCEDURE,
 ALTER_INDEX, DROP_INDEX,
 ALTER_TABLE, DROP_TABLE, ALTER_TRIGGER, DROP_TRIGGER,
 ALTER_VIEW, DROP_VIEW, ALTER_SCHEMA, DROP_SCHEMA,
 ALTER_ROLE, DROP_ROLE, ALTER_USER, DROP_USER
AS
SET NOCOUNT ON
INSERT dbo.ChangeAttempt
(EventData, DBUser)
VALUES (EVENTDATA(), USER)
GO

我的问题是：如何以编程方式在一次运行中创建 DDL 触发器？

Answer 1

为什么你需要跑一趟？这是唯一的方法。

Msg 111, Level 15, State 1, Line 2
'CREATE TRIGGER' must be the first statement in a query batch.

运行由此生成的输出：

DECLARE @DatabaseName varchar(500)
DECLARE @Database_id  int
DECLARE @Query        varchar(8000)
DECLARE @CRLF         char(2)

SET @CRLF=CHAR(13)+CHAR(10)
---MODIFY THIS TO INCLUDE THE DATABASES THAT YOU WANT TO WORk ON
---MODIFY THIS TO INCLUDE THE DATABASES THAT YOU WANT TO WORk ON
select @Database_id=MIN(database_id) from sys.databases where database_id IN (5,7,8,6)

WHILE @Database_id IS NOT NULL
BEGIN
    SELECT @DatabaseName=name from sys.databases where database_id=@Database_id
    SET @Query='-- Create table'+@CRLF+@CRLF
                +'use '+@DatabaseName+@CRLF
                +' GO'+@CRLF
                +' CREATE TABLE dbo.ChangeAttempt'+@CRLF
                +' (EventData xml NOT NULL,'+@CRLF
                +' AttemptDate datetime NOT NULL DEFAULT GETDATE(),'+@CRLF
                +' DBUser char(50) NOT NULL)'+@CRLF
                +'GO'+@CRLF+@CRLF
                +'-- Create DDL trigger '+@CRLF+@CRLF
                +'use '+@DatabaseName+@CRLF
                +'GO'+@CRLF
                +'CREATE TRIGGER db_trg_ObjectChanges'+@CRLF
                +'ON DATABASE'+@CRLF
                +'FOR ALTER_PROCEDURE, DROP_PROCEDURE,'+@CRLF
                +' ALTER_INDEX, DROP_INDEX,'+@CRLF
                +' ALTER_TABLE, DROP_TABLE, ALTER_TRIGGER, DROP_TRIGGER,'+@CRLF
                +' ALTER_VIEW, DROP_VIEW, ALTER_SCHEMA, DROP_SCHEMA,'+@CRLF
                +' ALTER_ROLE, DROP_ROLE, ALTER_USER, DROP_USER'+@CRLF
                +'AS'+@CRLF
                +'SET NOCOUNT ON'+@CRLF
                +'INSERT dbo.ChangeAttempt'+@CRLF
                +'(EventData, DBUser)'+@CRLF
                +'VALUES (EVENTDATA(), USER)'+@CRLF
                +'GO'+@CRLF
    PRINT @Query
    ---MODIFY THIS TO INCLUDE THE DATABASES THAT YOU WANT TO WORk ON
    ---MODIFY THIS TO INCLUDE THE DATABASES THAT YOU WANT TO WORk ON
    select @Database_id=MIN(database_id) from sys.databases WHERE database_id IN (5,7,8,6) AND database_id>@Database_id
END

编辑
要确定为其生成脚本的数据库，请执行以下操作：

• 运行此查询：

  从 sys.databases 中选择数据库 ID、名称

• 找到您想要运行脚本的所有数据库

• 改变我上面的脚本 在两个地方 （在循环之前和循环底部）因此您想要的所有database_id都在以下代码部分中：

  WHERE 数据库 ID IN (AAA,BBB,CCC,DDD,....)

Answer 2

您可以使用sp_MSforeachdb。

像这样

sp_MSforeachdb
'
    CREATE TABLE ?.dbo.ChangeAttempt
        etc. etc. etc.
'
sp_MSforeachdb
'
    CREATE TRIGGER ?.dbo.db_trg_ObjectChanges
        etc. etc. etc.
'

我没有测试过这一点，在理论上我希望它的工作，虽然。你要确保你排除系统数据库，但。