SWIFT编译错误BITCAST需要两个操作数要指向指针或既不是

Question

在xcode6 beta中，类似于这的东西，但是用xcode6 beta 4有误差。修复错误后，无错误代码我的位置低于

背景： 我在这里使用的课程实现了生成的，它允许用户从地址簿中选择联系人。我想收到添加到该人的第一封电子邮件。

func peoplePickerNavigationController(peoplePicker: ABPeoplePickerNavigationController!,didSelectPerson person: ABRecordRef!) {

    var emails = ABRecordCopyValue(person, kABPersonEmailProperty)
    var emailsObj = emails.takeUnretainedValue() as AnyObject
    var index = 0 as CFIndex
    var emailAddress = ABMultiValueCopyValueAtIndex(emailsObj, index)

    println(emailAddress)
}

. 但是，当我编译时，我获得构建失败：

bitcast需要两个操作数是指针还是既不是 ％80= bitcast％objc_object *％79到％pss9anyobject_，！dbg！860 存储的值类型与指针操作数类型不匹配！ 存储％pss9anyobject_％80，％objc_object **％81，对齐4，！dbg！860 ％objc_object *存储的值类型与指针操作数类型不匹配！ Store％PSS9AnyObject_％80，％objc_object **％85，对齐4，！dbg！864 ％objc_object * llvm错误：找到损坏功能，编译中止！ 命令/应用程序/ xcode6-beta4.app/contents/developer/toolchains/xcodedefault.xctoolchain/usr/bin/swift失败，退出代码1

嫌疑线是：

var emailsObj = emails.takeUnretainedValue() as AnyObject
var emailAddress = ABMultiValueCopyValueAtIndex(emailsObj, index)

.

当我将代码更改为

时

func peoplePickerNavigationController(peoplePicker: ABPeoplePickerNavigationController!,didSelectPerson person: ABRecordRef!) {

    var emails = ABRecordCopyValue(person, kABPersonEmailProperty)
    var emailsObj:AnyObject? = emails.takeRetainedValue() as AnyObject
    var index = 0 as CFIndex
    var emailAddress = ABMultiValueCopyValueAtIndex(emailsObj, index)

    println(emailAddress)
}

.

错误缩短到

bitcast需要两个操作数是指针还是既不是 ％79= bitcast％objc_object *％78到％pss9anyobject_，！dbg！856 存储的值类型与指针操作数类型不匹配！ Store％PSS9AneObject_％79，％objc_object **％80，align 8，！dbg！856 ％objc_object * llvm错误：找到损坏功能，编译中止！ 命令/应用程序/ xcode6-beta4.app/contents/developer/toolchains/xcodedefault.xctoolchain/usr/bin/swift失败，退出代码1

提前感谢任何帮助

亚伦

Answer 1

func peoplePickerNavigationController(peoplePicker: ABPeoplePickerNavigationController!,didSelectPerson person: ABRecordRef!) {

    var unmanagedEmails = ABRecordCopyValue(person, kABPersonEmailProperty)
    let emailObj: ABMultiValueRef = Unmanaged.fromOpaque(unmanagedEmails.toOpaque()).takeUnretainedValue() as NSObject as ABMultiValueRef

    var index = 0 as CFIndex

    var unmanagedEmail = ABMultiValueCopyValueAtIndex(emailObj, index)
    var emailAddress:String = Unmanaged.fromOpaque(unmanagedEmail.toOpaque()).takeUnretainedValue() as NSObject as String

    println(emailAddress)

}

.

更完整的答案可以找到这里。