C＃SHA1与PHP SHA1 ......不同的结果？

Question

我想从一个字符串计算SHA-1散列，但是当我使用PHP的SHA1函数计算字符串我得到的东西比我尝试在C＃不同。我需要C＃来计算相同的字符串作为PHP（因为从PHP字符串由我不能修改第三方计算）。我怎样才能获得C＃生成相同的散列为PHP？感谢!!!

的字符串= s934kladfklada@a.com

C＃代码（生成d32954053ee93985f5c3ca2583145668bb7ade86）

        string encode = secretkey + email;
        UnicodeEncoding UE = new UnicodeEncoding();
        byte[] HashValue, MessageBytes = UE.GetBytes(encode);
        SHA1Managed SHhash = new SHA1Managed();
        string strHex = "";

        HashValue = SHhash.ComputeHash(MessageBytes);
        foreach(byte b in HashValue) {
            strHex += String.Format("{0:x2}", b);
        }

PHP代码（生成a9410edeaf75222d7b576c1b23ca0a9af0dffa98）

sha1();

Answer 1

使用ASCIIEncoding代替UnicodeEncoding。 PHP使用ASCII字符用于散列计算。

Answer 2

这个方法在.NET相当于在PHP SHA1：

string sha1Hash(string password)
{
    return string.Join("", SHA1CryptoServiceProvider.Create().ComputeHash(Encoding.UTF8.GetBytes(password)).Select(x => x.ToString("x2")));
}

Answer 3

我也有这个问题。下面的代码将正常工作。

string dataString = "string to hash";
SHA1 hash = SHA1CryptoServiceProvider.Create();
byte[] plainTextBytes = Encoding.ASCII.GetBytes(dataString);
byte[] hashBytes = hash.ComputeHash(plainTextBytes);
string localChecksum = BitConverter.ToString(hashBytes)
.Replace("-", "").ToLowerInvariant();

Answer 4

有同样的问题。此代码为我工作：

string encode = secretkey + email;
SHA1 sha1 = SHA1CryptoServiceProvider.Create();
byte[] encodeBytes = Encoding.ASCII.GetBytes(encode);
byte[] encodeHashedBytes = sha1.ComputeHash(passwordBytes);
string pencodeHashed = BitConverter.
ToString(encode HashedBytes).Replace("-", "").ToLowerInvariant();

Answer 5

FWIW，我在Java中也有类似的问题。原来，我不得不使用“UTF-8”编码以产生相同的SHA1在Java中散列作为sha1函数在PHP 5.3.1产生（上XAMPP Vista中运行）。

    private static String SHA1(final String text) throws NoSuchAlgorithmException, UnsupportedEncodingException {
        final MessageDigest md = MessageDigest.getInstance("SHA-1");
        md.update(text.getBytes("UTF-8"));
        return new String(org.apache.commons.codec.binary.Hex.encodeHex(md.digest()));
    }

Answer 6

尝试以下方法！我认为这会是不错的：

public static string SHA1Encodeb64(string toEncrypt)
    {
        //Produce an array of bytes which is the SHA1 hash
        byte[] sha1Signature = new byte[40];

        byte[] sha = System.Text.Encoding.Default.GetBytes(toEncrypt);
        SHA1 sha1 = SHA1Managed.Create();
        sha1Signature = sha1.ComputeHash(sha);


        /**
        * The BASE64 encoding standard's 6-bit alphabet, from RFC 1521,
        * plus the padding character at the end.
        */
        char[] Base64Chars = {
            'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H',
            'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P',
            'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X',
            'Y', 'Z', 'a', 'b', 'c', 'd', 'e', 'f',
            'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n',
            'o', 'p', 'q', 'r', 's', 't', 'u', 'v',
            'w', 'x', 'y', 'z', '0', '1', '2', '3',
            '4', '5', '6', '7', '8', '9', '+', '/',
            '='
            };
        //Algorithm to encode the SHA1 hash using Base64
        StringBuilder sb = new StringBuilder();
        int len = sha1Signature.Length;
        int i = 0;
        int ival;
        while (len >= 3)
        {
            ival = ((int)sha1Signature[i++] + 256) & 0xff;
            ival <<= 8;
            ival += ((int)sha1Signature[i++] + 256) & 0xff;
            ival <<= 8;
            ival += ((int)sha1Signature[i++] + 256) & 0xff;
            len -= 3;
            sb.Append(Base64Chars[(ival >> 18) & 63]);
            sb.Append(Base64Chars[(ival >> 12) & 63]);
            sb.Append(Base64Chars[(ival >> 6) & 63]);
            sb.Append(Base64Chars[ival & 63]);
        }
        switch (len)
        {
            case 0: // No pads needed.
                break;
            case 1: // Two more output bytes and two pads.
                ival = ((int)sha1Signature[i++] + 256) & 0xff;
                ival <<= 16;
                sb.Append(Base64Chars[(ival >> 18) & 63]);
                sb.Append(Base64Chars[(ival >> 12) & 63]);
                sb.Append(Base64Chars[64]);
                sb.Append(Base64Chars[64]);
                break;
            case 2: // Three more output bytes and one pad.
                ival = ((int)sha1Signature[i++] + 256) & 0xff;
                ival <<= 8;
                ival += ((int)sha1Signature[i] + 256) & 0xff;
                ival <<= 8;
                sb.Append(Base64Chars[(ival >> 18) & 63]);
                sb.Append(Base64Chars[(ival >> 12) & 63]);
                sb.Append(Base64Chars[(ival >> 6) & 63]);
                sb.Append(Base64Chars[64]);
                break;
        }
        //Encode the signature using Base64
        string base64Sha1Signature = sb.ToString();
        return base64Sha1Signature;
    }