阅读datagridview
-
01-07-2019 - |
题
我从数据表中填充了datagridview。如何在应用程序运行时从datagridview读取?
解决方案
你是如何填充它的? DataSource是一个像BindlingList一样有用的东西吗? 如果是这样的话:
BindingSource bindingSource = this.dataGridView1.DataSource as BindingSource;
//substitute your business object type for T
T entity = bindingSource.Current as T;
会得到绑定到该行的实体。
否则总会有datagridview.Columns [n] .Cells [n] .Value,但实际上我会考虑使用DataSource中的对象
编辑:啊......一个数据表......右边:
var table = dataGridView1.DataSource as DataTable;
foreach(DataRow row in table.Rows)
{
foreach(DataColumn column in table.Columns)
{
Console.WriteLine(row[column]);
}
}
其他提示
您可以遍历数据网格视图并检索每个单元格。
for(int i =0; i < DataGridView.Rows.Count; i++){
DataGridView.Rows.Columns["columnName"].Text= "";
}
此处有一个示例。
您可能需要查看 DataTable .WriteXml ,它的兄弟 DataTable。的ReadXml 。没有大惊小怪,没有保存数据表。
namespace WindowsFormsApplication2
{
public partial class Form1 : Form
{
public static DataTable objDataTable = new DataTable("UpdateAddress");
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
Stream myStream = null;
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.InitialDirectory = "c:\\";
openFileDialog1.Filter = "csv files (*.csv)|*.txt|All files (*.*)|*.*";
openFileDialog1.FilterIndex = 2;
openFileDialog1.RestoreDirectory = true;
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = openFileDialog1.OpenFile()) != null)
{
string fileName = openFileDialog1.FileName;
List<string> dataFile = new List<string>();
dataFile = ReadList(fileName);
foreach (string item in dataFile)
{
string[] temp = item.Split(',');
DataRow objDR = objDataTable.NewRow();
objDR["EmployeeID"] = temp[0].ToString();
objDR["Street"] = temp[1].ToString();
objDR["POBox"] = temp[2].ToString();
objDR["City"] = temp[3].ToString();
objDR["State"] = temp[4].ToString();
objDR["Zip"] = temp[5].ToString();
objDR["Country"] = temp[6].ToString();
objDataTable.Rows.Add(objDR);
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
}
public static List<string> ReadList(string filename)
{
List<string> fileData = new List<string>();
StreamReader sr = new StreamReader(filename);
while (!sr.EndOfStream)
fileData.Add(sr.ReadLine());
return fileData;
}
private void Form1_Load(object sender, EventArgs e)
{
objDataTable.Columns.Add("EmployeeID", typeof(int));
objDataTable.Columns.Add("Street", typeof(string));
objDataTable.Columns.Add("POBox", typeof(string));
objDataTable.Columns.Add("City", typeof(string));
objDataTable.Columns.Add("State", typeof(string));
objDataTable.Columns.Add("Zip", typeof(string));
objDataTable.Columns.Add("Country", typeof(string));
objDataTable.Columns.Add("Status", typeof(string));
dataGridView1.DataSource = objDataTable;
dataGridView1.Refresh();
}
private void button2_Click(object sender, EventArgs e)
{
// Displays a SaveFileDialog so the user can save the backup of AD address before the update
// assigned to Button2.
SaveFileDialog saveFileDialog1 = new SaveFileDialog();
saveFileDialog1.Filter = "BAK Files|*.BAK";
saveFileDialog1.Title = "Save AD Backup";
saveFileDialog1.ShowDialog();
if (saveFileDialog1.FileName != "")
{
TextWriter fileOut = new StreamWriter(saveFileDialog1.FileName);
//This is where I want read from the datagridview the EmployeeID column and use it in my BackupAddress method.
}
}
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