使用在Python sqlite3的保存点

Question

我试图使用保存点与内置到蟒2.6 sqlite3的模块。每次我尝试发布或回滚的保存点，我总是收到一封OperationalError: no such savepoint。我缺少什么？

python version: 2.6.4 (r264:75821M, Oct 27 2009, 19:48:32) 
[GCC 4.0.1 (Apple Inc. build 5493)]
PySQLite version: 2.4.1
sqlite3 version: 3.6.11

Traceback (most recent call last):
  File "spDemo.py", line 21, in <module>
    conn.execute("release savepoint spTest;")
sqlite3.OperationalError: no such savepoint: spTest

从这个代码：

import sys
import sqlite3

print 'python version:', sys.version
print 'PySQLite version:', sqlite3.version
print 'sqlite3 version:', sqlite3.sqlite_version
print

conn = sqlite3.connect('db_spDemo.db')
conn.isolation_level = "DEFERRED"

with conn:
    conn.execute("create table example (A, B);")

with conn:
    conn.execute("insert into example values (?, ?);", (0,200))

    conn.execute("savepoint spTest;")
    conn.execute("insert into example values (?, ?);", (1,201))
    conn.execute("insert into example values (?, ?);", (2,202))
    conn.execute("release savepoint spTest;")

    conn.execute("insert into example values (?, ?);", (5,205))

Answer 1

这似乎是的sqlite3的模块与隔离级别的行为的结果。

这个作品，注意到两个更改：

import sys
import sqlite3

print 'python version:', sys.version
print 'PySQLite version:', sqlite3.version
print 'sqlite3 version:', sqlite3.sqlite_version
print

conn = sqlite3.connect('shane.sqlite')
conn.isolation_level = None  # CHANGED

with conn:
    conn.execute("create table example (A, B);")

with conn:
    conn.execute("insert into example values (?, ?);", (0,200))

    conn.execute("savepoint spTest;")
    conn.execute("insert into example values (?, ?);", (1,201))
    conn.execute("insert into example values (?, ?);", (2,202))
    conn.execute("rollback to savepoint spTest;")  # CHANGED

    conn.execute("insert into example values (?, ?);", (5,205))

输出：

$ python shane-sqlite3.py && sqlite3 shane.sqlite 'select * from example;'
python version: 2.6.2 (release26-maint, Apr 19 2009, 01:56:41) 
[GCC 4.3.3]
PySQLite version: 2.4.1
sqlite3 version: 3.6.10

0|200
5|205

这是不能令人满意的答案，我没有看到在sqlite3的模块文档相关的任何事情（我也没有尝试看看源）。但我希望它可以帮助你找到正确的方向。

Answer 2

这是在pysqlite一个错误，请参阅的pysql问题跟踪器和蟒问题跟踪器。