iPhone Uibutton具有UISWitch功能

Question

是否有一种使用自定义图形为开关状态实现UISWitch的方法？还是作为替代方案的替代方案，是带有UISWitch功能的Uibutton？

Answer 1

UIButton 已经支持“开关”功能。

只需在接口构建器中为“选定状态配置”设置其他图像，然后使用 selected 财产的 UIButton 切换其状态。

Answer 2

设置要在选定状态显示的图像：

[button setImage:[UIImage imageNamed:@"btn_graphics"] forState:UIControlStateSelected];

然后在选择器内部进行修饰，设置：

button.selected = YES;

如果您希望它取消另一个按钮的选择，请设置：

otherButton.selected = NO;

Answer 3

为了构建PGB和Nurne上面所说的内容，在设置状态并附加选择器（事件方法）之后，您希望将此代码放入该选择器中。

- (IBAction)cost:(id)sender 
{
    //Toggle current state and save
    self.buttonTest.selected = !self.buttonTest.selected;

    /**
     The rest of your method goes here.
     */
}

Answer 4

用于编程倾斜：

-(void) addToggleButton {
    CGRect aframe = CGRectMake(0,0,100,100);

    UIImage *selectedImage = [UIImage imageNamed:@"selected"];
    UIImage *unselectedImage = [UIImage imageNamed:@"unselected"];

    self.toggleUIButton = [[UIButton alloc] initWithFrame:aframe];
    [self.toggleUIButton setImage:unselectedImage forState:UIControlStateNormal];
    [self.toggleUIButton setImage:selectedImage forState:UIControlStateSelected];
    [self.toggleUIButton addTarget:self 
                            action:@selector(clickToggle:) 
                  forControlEvents:UIControlEventTouchUpInside];
    [self addSubview:self.toggleUIButton];
}

-(void) clickToggle:(id) sender {
    BOOL isSelected = [(UIButton *)sender isSelected];
    [(UIButton *) sender setSelected:!isSelected];
}