SQL服务器 - 顶级销售员每个地区

StackOverflow https://stackoverflow.com/questions/2294653

  •  21-09-2019
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题 

    SELECT region, person, sum(dollars) as thousands
    FROM sales
    GROUP BY region, person
    ORDER BY region, sum(dollars) desc

在SQL上述生产销售人的完整列表每个区域这样

    region person      thousands

    canada mike smith  $114
    canada joe blog    $76
    canada pete dodd   $45
    usa    john doe    $253
    usa    jane smyth  $120
    europe pieter tsu  $546
    europ  mike lee    $520

如果我只示出在每个区域顶端营业员感兴趣（如下），我怎样才能最好做呢？

    region person      thousands

    canada mike smith  $114
    usa    john doe    $253
    europe pieter tsu  $546
有帮助吗？

解决方案

我已经做了一些类似burnall建议。我没有得到太多的爱与“顶1的关系”的一部分，所以我做了整个事情的子查询并选择行，其中排名= 1。

select *
from
(
     select region, 
            person, 
            rank() over(partition by region order by sum(dollars) desc) as ranking
     from sales 
     group by region, 
              person 

) temp
where ranking = 1

请注意，这也适用于领带，因为秩（）似乎将在同一排名上是相等的款项。

其他提示

使用SQL Server 2005 +，你可以做到这一点使用 ROW_NUMBER（）

有一个在这个完整的例子。

DECLARE @sales TABLE(
        region VARCHAR(50), 
        person VARCHAR(50),
        Sales FLOAT
)



INSERT INTO @sales SELECT 'canada','mike smith',1 
INSERT INTO @sales SELECT 'canada','mike smith',1
INSERT INTO @sales SELECT 'canada','mike smith',1
INSERT INTO @sales SELECT 'canada','mike smith',1

INSERT INTO @sales SELECT 'canada','joe blog',1
INSERT INTO @sales SELECT 'canada','joe blog',1 

INSERT INTO @sales SELECT 'canada','pete dodd',1 


INSERT INTO @sales SELECT 'usa','john doe',1
INSERT INTO @sales SELECT 'usa','john doe',1

INSERT INTO @sales SELECT 'usa','jane smyth',1

INSERT INTO @sales SELECT 'europe','pieter tsu',1
INSERT INTO @sales SELECT 'europe','pieter tsu',1 

INSERT INTO @sales SELECT 'europe','mike lee',1

;WITH Counts AS(
        SELECT  region, 
                person, 
                count(*) as thousands 
        FROM    @sales 
        GROUP BY    region, 
                    person
), CountVals AS(
        SELECT  *,
                ROW_NUMBER() OVER(PARTITION BY region ORDER BY thousands DESC) ROWID
        FROM     Counts
)
SELECT  *
FROM    CountVals
WHERE   ROWID = 1

在SQL Server 2005和以上使用ROW_NUMBER与PARTITION BY。以下应该工作（未测试，大概可以缩短）：

WITH total_sales
AS (SELECT      region, person, count(*) as thousands
    FROM        sales
    GROUP BY    region, person
    ORDER BY    region, count(*) desc
)
, ranked_sales
AS (SELECT      region, person, thousands,
                ROW_NUMBER() OVER (PARTITION BY region ORDER BY thousands DESC, person) AS region_rank
    FROM        total_sales
)
SELECT  region, person, thousands
FROM    ranked_sales
WHERE   region_rank = 1

首先，我不明白为什么COUNT（*）是$。 我的解决办法是类似于现有的，但较短的，我相信更快

select top 1 with ties region, person, rank() over(partition by region order by count(*) desc)
from sales
group by region, person
order by 3

这是不是太困难。该查询将不正是你想要的。

 select distinct region,
        (select top 1 person
        from Sales s2 where s2.region = s1.region
        group by person
        order by SUM(dollars) desc) as person,
            (select top 1 SUM(dollars) 
        from Sales s2 where s2.region = s1.region
        group by person
        order by SUM(dollars) desc) as thousands
        from sales s1

可以使用最大值（）骨料。它可能比其他替代效率较低，因为你会被两次

做组 
SELECT region,person,max(thousands) FROM
(SELECT region, person, count(*) as thousands
FROM sales
GROUP BY region, person) tmp
GROUP BY region, person
ORDER BY region, max(thousands) desc

找到顶部5销售人员通过销售针对每个区域

select *
from
(
     select region, 
            [Customer Name],
            rank() over(partition by region order by sum(sales) desc) as ranking
     from Orders 
     group by region, [Customer Name] 
) temp
where ranking between 1 and 5
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