题
我想做的事情是这样的:
public enum Permissions
{
CanBlah1,
CanBlah2,
CanBlah3
}
byte[] userPerm = Permissions.CanBlah1 | Permissions.CanBlah2;
// check permssions
//
if(userPerm && Permissions.CanBlah1 == Permissions.CanBlah1)
{
// do something
}
可以做到这一点在Java中这样呢? (我从C#背景的)
解决方案
可以很容易地使用EnumSet
做
import java.util.EnumSet;
import static java.util.EnumSet.of;
import static java.util.EnumSet.range;
import static so.User.Permissions.CanBlah1;
import static so.User.Permissions.CanBlah2;
import static so.User.Permissions.CanBlah3;
public class User {
public enum Permissions {
CanBlah1,
CanBlah2,
CanBlah3
}
public static void main(String[] args) throws Exception {
EnumSet<Permissions> userPerms = of(CanBlah1, CanBlah2);
System.out.println(userPerms.contains(CanBlah1)); //true
System.out.println(userPerms.contains(CanBlah2)); //true
System.out.println(userPerms.contains(CanBlah3)); //false
System.out.println(userPerms.containsAll(of(CanBlah1, CanBlah3))); //false
System.out.println(userPerms.containsAll(range(CanBlah1, CanBlah2))); //true
System.out.println(userPerms.containsAll(range(CanBlah1, CanBlah3))); //false
}
}
其他提示
这是另一种选择,这是类似的序溶液,不同之处在于可以使用|和&与此操作符:
public enum Permissions {
CanBlah1(1),
CanBlah2(2),
CanBlah3(4);
public int value;
Permissions(int value) {
this.value = value;
}
public int value() {
return value;
}
}
public static void main(String[] args) {
int userPerm = Permissions.CanBlah1.value() | Permissions.CanBlah2.value();
// check permssions
//
if((userPerm & Permissions.CanBlah1.value()) == Permissions.CanBlah1.value())
{
// do something
}
}
或:
public enum Permissions {
CanBlah1,
CanBlah2,
CanBlah3;
public int value() {
return 1<<ordinal();
}
}
public static void main(String[] args) {
int userPerm = Permissions.CanBlah1.value() | Permissions.CanBlah2.value();
// check permssions
//
if((userPerm & Permissions.CanBlah1.value()) == Permissions.CanBlah1.value())
{
// do something
}
}
虽然我不会推荐它,你可以要求枚举的顺序(),并使用该位操作。当然,因为你无法定义的顺序是什么枚举的,你必须插入伪造的值,以获得正确的序
enum Example {
Bogus, --> 0
This, --> 1
That, --> 2
ThisOrThat --> 3
};
注意需要引入一个虚假的枚举,使得
ThisOrThat.ordinal() == This.ordinal() | That.ordinal()
如果你在预Java 7的时代(机器人)卡住可以尝试以下代码:
public enum STUFF_TO_BIT_BASK {
THIS,THAT,OTHER;
public static int getBitMask(STUFF_TO_BIT_BASK... masks) {
int res = 0;
for (STUFF_TO_BIT_BASK cap : masks) {
res |= (int) Math.pow(2, cap.ordinal());
}
return res;
}
public boolean is(int maskToCheck){
return maskToCheck | (int) Math.pow(2, this.ordinal());
}
}
据我知道位运算符没有定义枚举类型
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