仅使用linqtoxml从XML读取父节点

Question

我有XML字符串，上面有父母节点“委员会”，在另一个儿童节点“委员会”中。当我使用的时候from committee in xDocument.DescendantsAndSelf("Committee")“它还正在阅读儿童节点，但我不想阅读子节点，我只想只阅读父节点。

<Committee>
  <Position>STAFF</Position>
  <Appointment>1/16/2006</Appointment>
  <Committee>PPMSSTAFF</Committee>
  <CommitteeName>PPMS Staff</CommitteeName>
  <Expiration>12/25/2099</Expiration>      
</Committee>
<Committee>
   <Position>STAFF</Position>
  <Appointment>4/16/2004</Appointment>
  <Committee>PMOSSTAFF</Committee>
  <CommitteeName>PPMS </CommitteeName>
  <Expiration>12/25/2099</Expiration>
</Committee>

     XElement xDocument= XElement.Parse(xml);

 var committeeXmls = from Committee in xDocument.Descendants("Committee")
                                select new
                                {
                                    CommitteeName = Committee.Element("CommitteeName"),
                                    Position = Committee.Element("Position"),
                                    Appointment = Committee.Element("Appointment"),
                                    Expiration = Committee.Element("Expiration")
                                };

            int i = 0;
            foreach (var committeeXml in committeeXmls)
            {
                if (committeeXml != null)
                {
                    drCommittee = dtCommittee.NewRow();
                    drCommittee["ID"] = ++i;
                    drCommittee["CommitteeName"] = committeeXml.CommitteeName.Value;
                    drCommittee["Position"] = committeeXml.Position.Value;
                    drCommittee["Appointment"] = committeeXml.Appointment.Value;
                    drCommittee["Expiration"] = committeeXml.Expiration.Value;

                    dtCommittee.Rows.Add(drCommittee);                                        //   educationXml.GraduationDate.Value, educationXml.Major.Value);
                }
            }

Answer 1

使用 Elements 方法而不是 Descendants.

更改此：

from Committee in xDocument.Descendants("Committee")

为此：

from Committee in xDocument.Elements("Committee")

这将返回孩子 Committee 当前元素的元素（xDocument 多变的）。

Answer 2

您可以使用XPathSelectelements扩展方法（在System.xml.XPath名称空间中）仅选择具有委员会子元素的委员会元素。

var committeeXmls = from Committee in xDocument.XPathSelectElements("Committee[Committee]")
                    ...