# 从出生和今天的日期甲骨文年龄计算

### 解

``````SQL> select trunc(months_between(sysdate,dob)/12) year,
2         trunc(mod(months_between(sysdate,dob),12)) month,
4  from (Select to_date('15122000','DDMMYYYY') dob from dual);

YEAR      MONTH        DAY
---------- ---------- ----------
9          5         26

SQL>
``````

### 其他提示

``````select months_between(TRUNC(sysdate),
to_date('15-Dec-2000','DD-MON-YYYY')
)/12
as age from dual;

AGE
----------
9.48924731
``````

``````SELECT
TRUNC((SYSDATE - TO_DATE(DOB, 'YYYY-MM-DD'))/ 365.25) AS AGE_TODAY FROM DUAL;
``````

``````SQL> with some_birthdays as
2  ( select date '1968-06-09' d from dual union all
3    select date '1970-06-10' from dual union all
4    select date '1972-06-11' from dual union all
5    select date '1974-12-11' from dual union all
6    select date '1976-09-17' from dual
7  )
8  select trunc(sysdate) today
9       , d birth_date
10       , extract(year from numtoyminterval(months_between(trunc(sysdate),d),'month')) age
11    from some_birthdays
12  /

TODAY               BIRTH_DATE                 AGE
------------------- ------------------- ----------
10-06-2010 00:00:00 09-06-1968 00:00:00         42
10-06-2010 00:00:00 10-06-1970 00:00:00         40
10-06-2010 00:00:00 11-06-1972 00:00:00         37
10-06-2010 00:00:00 11-12-1974 00:00:00         35
10-06-2010 00:00:00 17-09-1976 00:00:00         33

5 rows selected.
``````

``````with some_birthdays as
(
select date '1968-06-09' d from dual union all
select date '1970-06-10' from dual union all
select date '1972-06-11' from dual union all
select date '1974-12-11' from dual union all
select date '1976-09-17' from dual
)
select trunc(sysdate) today
, d birth_date
, floor(months_between(trunc(sysdate),d)/12) age
from some_birthdays;
``````

``````select sysdate-to_date('30-jul-1977') from dual;
``````

``````SELECT
TRUNC(months_between(sysdate, per.DATE_OF_BIRTH) / 12) AS "Age"
FROM PD_PERSONS per
``````

``````SQL>select to_char(to_date('19-11-2017','dd-mm-yyyy'),'yyyy') -  to_char(to_date('10-07-1986','dd-mm-yyyy'),'yyyy') year,
to_char(to_date('19-11-2017','dd-mm-yyyy'),'mm') -  to_char(to_date('10-07-1986','dd-mm-yyyy'),'mm') month,
to_char(to_date('19-11-2017','dd-mm-yyyy'),'dd') -  to_char(to_date('10-07-1986','dd-mm-yyyy'),'dd') day from dual;

YEAR      MONTH        DAY
---------- ---------- ----------
31          4          9
``````

``````SELECT ROUND((SYSDATE - TO_DATE('12-MAY-16'))/365.25, 5) AS AGE from DUAL;
``````

``````SELECT TRUNC(TO_NUMBER(SYSDATE - TO_DATE('04-06-1996')) / 365.25) AS AGE FROM DUAL;
``````

### 结果：（执行的2019年5月28日）

``````       AGE
----------
22
``````

### 说明：

• `SYSDATE`：获取系统（OS）的实际日期
• `TO_DATE('04-06-1996')`：转换`VARCHAR`（字符串）出生日期到`DATE`（SQL型）
• `TO_NUMBER(...)`：转换的日期`NUMBER`（SQL型）
• Devide每`365.25`：为了有一个闰年每四年（4 * 0.25 = 1更多天）。
• `Trunc(...)`：只从多个检索整个部分

`SELECT EXTRACT(YEAR FROM APP_SUBMITTED_DATE)-EXTRACT(YEAR FROM BIRTH_DATE) FROM SOME_TABLE;`