通过使用基团和具有在JPA查询

Question

你会怎么做使用JPA查询语言以下？

select * from person where email in
(select email from person group by email having count(email)>1)

Answer 1

最后找到了解决方案：

select p from Person p
where p.email in (
    select q.email
    from Person q
    group by q.email having count(q.email)>1)
order by p.email, p.id

Answer 2

从此链接，还有的一般结构的解释一个JPA SELECT查询：

SELECT ... FROM ...
[WHERE ...]
[GROUP BY ... [HAVING ...]]
[ORDER BY ...]