Objective-C NSFilePosixpermissmiss of Human可读性NSString

Question

有没有办法从nsfileposixpermissions Integer中获取人类可读字符串（例如@“ drwxr-xr-x”）？

Answer 1

文件系统权限属性只是一个无符号的长度值。下面的代码显然可以提高效率，但它（或多或少）显示了要获得所需的字符串需要做的事情：

// The indices of the items in the permsArray correspond to the POSIX
// permissions. Essentially each bit of the POSIX permissions represents
// a read, write, or execute bit.
NSArray *permsArray = [NSArray arrayWithObjects:@"---", @"--x", @"-w-", @"-wx", @"r--", @"r-x", @"rw-", @"rwx", nil];
NSFileManager *fm = [[[NSFileManager alloc] init] autorelease];
NSMutableString *result = [NSMutableString string];
NSDictionary *attrs = [fm attributesOfItemAtPath:@"some/path.txt" error:NULL];

if (!attrs)
    return nil;

NSUInteger perms = [attrs filePosixPermissions];

if ([[attrs fileType] isEqualToString:NSFileTypeDirectory])
    [result appendString:@"d"];
else
    [result appendString:@"-"];

// loop through POSIX permissions, starting at user, then group, then other.
for (int i = 2; i >= 0; i--)
{
    // this creates an index from 0 to 7
    unsigned long thisPart = (perms >> (i * 3)) & 0x7;

    // we look up this index in our permissions array and append it.
    [result appendString:[permsArray objectAtIndex:thisPart]];
}

return result;

Answer 2

好吧，我想您可以创建一个类似的数组：

NSArray *convertToAlpha = [NSArray arrayWithObjects:@"---",@"--x",@"-w-",@"--wx",@"r--",@"r-x",@"rw-",@"rwx", nil];

然后，将NSFilePosixpermissions旋转到八进制后，将结果编号拆分为其组合数字，并使用converttoalpha将每个数字映射到其字母数字表示。