如何计算C＃中浮子的平方根

Question

我如何计算A的平方根 Float 在 C#, ， 如同 Core.Sqrt 在XNA中？

Answer 1

计算它 double 然后回到浮动。可能有点慢，但应该起作用。

(float)Math.Sqrt(inputFloat)

Answer 2

讨厌这么说，但是0x5F3759DF似乎需要3倍，直到数学。我只是对计时器进行了一些测试。在循环访问预定阵列的前循环中的Math.sqrt约为80ms。 0x5F3759DF在相同情况下导致180+ms

使用释放模式优化进行了几次测试。

来源下：

/*
    ================
    SquareRootFloat
    ================
    */
    unsafe static void SquareRootFloat(ref float number, out float result)
    {
        long i;
        float x, y;
        const float f = 1.5F;

        x = number * 0.5F;
        y = number;
        i = *(long*)&y;
        i = 0x5f3759df - (i >> 1);
        y = *(float*)&i;
        y = y * (f - (x * y * y));
        y = y * (f - (x * y * y));
        result = number * y;
    }

    /*
    ================
    SquareRootFloat
    ================
    */
    unsafe static float SquareRootFloat(float number)
    {
        long i;
        float x, y;
        const float f = 1.5F;

        x = number * 0.5F;
        y = number;
        i = *(long*)&y;
        i = 0x5f3759df - (i >> 1);
        y = *(float*)&i;
        y = y * (f - (x * y * y));
        y = y * (f - (x * y * y));
        return number * y;
    }

    /// <summary>
    /// The main entry point for the application.
    /// </summary>
    [STAThread]
    static void Main()
    {
        int Cycles = 10000000;
        Random rnd = new Random();
        float[] Values = new float[Cycles];
        for (int i = 0; i < Cycles; i++)
            Values[i] = (float)(rnd.NextDouble() * 10000.0);

        TimeSpan SqrtTime;

        float[] Results = new float[Cycles];

        DateTime Start = DateTime.Now;

        for (int i = 0; i < Cycles; i++)
        {
            SquareRootFloat(ref Values[i], out Results[i]);
            //Results[i] = (float)Math.Sqrt((float)Values[i]);
            //Results[i] = SquareRootFloat(Values[i]);
        }

        DateTime End = DateTime.Now;

        SqrtTime = End - Start;

        Console.WriteLine("Sqrt was " + SqrtTime.TotalMilliseconds.ToString() + " long");
        Console.ReadKey();
    }
}

Answer 3

var result = Math.Sqrt((double)value);

Answer 4

private double operand1;  

private void squareRoot_Click(object sender, EventArgs e)
{ 
    operand1 = Math.Sqrt(operand1);
    this.textBox1.Text = operand1.ToString();
}