jQuery检查无线电选项未检查

Question

我无法获取广播选项来检查我的页面。他们不会检查是或否。

                    for (var i = 0; i < r.length; i++) {
                        jQuery('#condition-'+i+'-price').val(r[i].price);
                        jQuery('#condition-'+i+'-bid').val(r[i].bid);
                        console.log('[value='+r[i].on_amazon+']');
                        console.log(jQuery('#condition-'+r[i].condition_id+'-on_amazon').filter('[value='+r[i].on_amazon+']'));
                        jQuery('#condition-'+r[i].condition_id+'-on_amazon').filter('[value='+r[i].on_amazon+']').attr('checked', true);
                    }

r [i] .on_amazon始终是1或0，条件_id是正确的，因为价格/出价成功更新...

<tr>
                            <td><label for="on_amazon-1-yes">Yes</label></td>
                            <td class="yes"><input type="radio" id="condition-1-on_amazon" value="1"></td>
                            <td>&nbsp;</td>
                            <td class="no"><input type="radio" id="condition-1-on_amazon" value="0"></td>
                            <td><label for="on_amazon-1-no">No</label></td>
                        </tr>

Answer 1

放 $(radiobtn).attr('checked','checked') 代替 true, ，假设您正在使用XHTML。

Answer 2

尝试做：

jQuery('#condition-'+r[i].condition_id+'-on_amazon').filter('[value='+r[i].on_amazon+']')[0].checked=true;