How can I left-pad the string representation of a float?
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06-07-2019 - |
Question
I'm trying to convert a single precision floating point number into an ascii representation of the four bytes that make it (sign/exponent/mantissa). My current code is:
Integer.toString(Float.floatToRawIntBits(f),16);
Float.floatToRawIntBits
makes an integer using the same bytes, and then Integer.toString
creates the ascii digits in hex form (hence the radix = 16 specified). My problem is that I always need 8 ascii characters plus the optional '-' sign, and Integer.toString
is not padding with left side zeroes.
Can anybody come up with an elegant solution?
Thanks.
Solution
You can use String.format():
String.format("%08x", Float.floatToRawIntBits(f))
This will zero-pad the result and format it as a hexadecimal number. Details on format strings can be found here.
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