What would be the right way to declare an array within a script that will be called by cron?
Question
I have written a KornShell (ksh) script that sets an array the following way:
set -A fruits Apple Orange Banana Strawberry
but when I am trying to run it from within cron, it raises the following error:
Your "cron" job on myhost
/myScript.sh
produced the following output:
myScript.sh: -A: bad option(s)
I have tried many crontab syntax variants, such as:
Attempt 1:
0,5,10,15,20,25,30,35,40,45,50,55 * * * * /path/to/script/myScript.sh
Attempt 2:
0,5,10,15,20,25,30,35,40,45,50,55 * * * * /path/to/script/./myScript.sh
Attempt 3:
0,5,10,15,20,25,30,35,40,45,50,55 * * * * cd /path/to/script && ./myScript.sh
Any workaround would be sincerely appreciated. Thanks much in advance!
Solution 3
Although I'm not sure it's the best way to do it, I've managed to solve it this way:
Attempt 4:
0,5,10,15,20,25,30,35,40,45,50,55 * * * * cd /path/to/script && ksh ./myScript.sh
OTHER TIPS
*/5 * * * * cd /path/to/script && ksh ./myScript.sh
:- it will run every 5 mins.
Define Path variables also in the cron itself.
Does myScript.sh
start with
#!/bin/ksh
(or whatever the path is for your ksh)?
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