How do i return a quoted string from a tuple?

Question

I have a tuple of strings that i would want to extract the contents as a quoted string, i.e.

tup=('string1', 'string2', 'string3')

when i do this

main_str = ",".join(tup)

#i get

main_str = 'string1, string2, string3'

#I want the main_str to have something like this

main_str = '"string1", "string2", "string3"'

Gath

Answer 1

", ".join('"{0}"'.format(i) for i in tup)

or

", ".join('"%s"' % i for i in tup)

Answer 2

Well, one answer would be:

', '.join([repr(x) for x in tup])

or

repr(tup)[1:-1]

But that's not really nice. ;)

Updated: Although, noted, you will not be able to control if resulting string starts with '" or '". If that matters, you need to be more explicit, like the other answers here are:

', '.join(['"%s"' % x for x in tup])

Answer 3

Here's one way to do it:

>>> t = ('s1', 's2', 's3')
>>> ", ".join( s.join(['"','"']) for s in t)
'"s1", "s2", "s3"'