Conventional Programming: How do you return two Types of primitive ('int and 'string') from "get" method?

Question

Trying to print out age and name of an Object using "get" method. However, my get method return type is string:

public String displayProfile() {
    System.out.print(getName() + getAge());

Hence the error:

This method must return a result of type String

Here is my main method: if user enters '2' from the "menu" where (2 == profile) the program should display user's name and age.

Side note: To select "friends" from menu, user will enter '3' (3 = friends).

public static void main(String[] args) {

// Initializing Objects
People zac = new People();
 zac.setName("zac");
 zac.setAge(18);

 People lisa = new  People();
 lisa.setName("lisa");
 lisa.setAge(19);

 // Zac be-friend LISA
 zac.addFriend("lisa");

    openApp();
    if(optionSelected == 3)
    {
       System.out.println(zac.getFriend());

       else if (optionSelected == 2) {
           System.out.println(zac.displayProfile());
        }
     }
       }

Being new to programming, I want to develop good programming practices, hence with this in mind; how would you display age and name of different type [int = age and string = name] from one method like i.e. public String displayProfile() OR is this completely wrong? Then what are the alternatives?

Additionally:

My getName() method:

// GET NAME 
    public String getName() {
        return this.name;
    }   

My setName() method:

 // SET NAME 
public  void setName(String name) {
    this.name = name;
    }

My getAge() method:

// GET AGE

    public int getAge() {
        return this.age;
    }

My setAge() method:

// SET AGE

    public void setAge(int age) {
        age = this.age;
        }

Answer 1

You can use String.format() with format specifiers (%s, %d, %f...)

public static String displayProfile()
{
    return String.format("%s %d", "StackOverflow", 6);
}

Note the return statement. It's totally different than System.out.print(...)

Also, the body of setAge() method, should look like:

this.age = age;

since you want to assign the age passed as parameter to the member this.age