Use slicing, specifying a step:
b,c = a[::2], a[1::2]
Use slicing, specifying a step:
b,c = a[::2], a[1::2]
Using filter is one option:
a = [item1, item2, item3, item4, item5, item6]
b = filter(lambda x: a.index(x) % 2 == 0, a)
c = filter(lambda x: a.index(x) % 2 != 0, a)
EDIT: This would require for the elements to be unique and is inefficient.