printing variable inside awk
https://stackoverflow.com/questions/1825509
Question
In this script , I want awk to print the variables $file
, $f
, $order
and sum/NR
(all in a single row)
#!/bin/bash
for file in pmb_mpi tau xhpl mpi_tile_io fftw ; do
for f in 2.54 1.60 800 ;do
if [ ${f} = 2.54 ]
then
for order in even odd ; do
# echo ${file}_${f}_${order}_v1.xls >> P-state-summary.xls
awk '{sum+=$2} END {print ${file}_${f}_${order}_v1.xls, sum/NR}' ${file}_${f}_${order}_v1.xls >> P-state-summary.xls
done
else
# echo ${file}_${f}_v1.xls >> P-state-summary.xls
awk '{sum+=$2} END {print ${file}_${f}_v1.xls , sum/NR}' ${file}_${f}_v1.xls >> P-state-summary.xls
fi
done
done
Colud anyone of you kindly help me with this ?
Solution
You can do this:
echo -n "${file}_${f}_${order}_v1.xls " >> P-state-summary.xls
# or printf "${file}_${f}_${order}_v1.xls " >> P-state-summary.xls
awk '{sum+=$2} END {print sum/NR}' "${file}_${f}_${order}_v1.xls" |
tee "${file}_${f}_avrg.xls" >> P-state-summary.xls
Using echo -n
or printf
without a "\n" will output the text without a newline so the output of the awk
command will follow it on the same line. I added a space as a separator, but you could use anything.
Using tee
will allow you to write your output to the individual files and the summary file using only one awk
invocation per input (order) file.
OTHER TIPS
awk
doesn't go out and get shell variables for you, you have to pass them in as awk
variables:
pax> export x=XX
pax> export y=YY
pax> awk 'BEGIN{print x "_" y}'
_
pax> awk -vx=$x -v y=$y 'BEGIN{print x "_" y}'
XX_YY
There is another way of doing it by using double quotes instead of single quotes (so that bash
substitutes the values before awk
sees them), but then you have to start escaping $
symbols and all sorts of other things in your awk
command:
pax> awk "BEGIN {print \"${x}_${y}\"}"
XX_YY
I prefer to use explicit variable creation.
By the way, there's another solution to your previous related question here which should work.