Trying to execute LIKE clause in sqlite3 in iPhone

Question

I am trying to execute LIKE clause in my sqlite3 query i.e.

sqlStatement = [NSString stringWithFormate;@"select * from table_name where column_name like '%"+%@+"%'",title];

Here title is a NSString type. having values like 6 Kt or 10 Kt or 14 Kt or 18 Kt

And in column_name i have values like this (6 Kt, 10 Kt, 14 Kt) in single statement

 |------------------------|
 |     column_name        |
 |------------------------|
 |   6 Kt, 10 Kt, 14 Kt   |
 | --------------------   |
 |   10 Kt, 18 Kt, 22 Kt  |
 | ---------------------  |
 |   6 Kt, 10 Kt, 24 Kt   |
 | ---------------------  |
 |   6 Kt, 14 Kt, 22 Kt   |
 | ---------------------- |
 |   6 Kt, 22 Kt, 24 Kt   | 
 | -----------------------|

and i try one more query like this :

sqlStatement = [NSString stringWithFormat:@"select * from jewelryInfo where karat like '%@%%'",title];

with the value of title = 6 Kt.

IT give the values of a row starting with 6 Kt

but when i try to use 18 Kt or 22 Kt as a value for title

it doesn't give me any result

I think it is only checking the first value of a row in this column.

please help me, Thanks

Answer 1

You must add a % before query. Also, you must use following query:

sqlStatement = [NSString stringWithFormat:@"select * from jewelryInfo where ', '||karat like '%% %@%%'",title];

to match items in middle, beginning or end of list and match 6 but not 16.