How do you test to see if a double is equal to NaN?

Question

I have a double in Java and I want to check if it is NaN. What is the best way to do this?

Answer 1

Use the static Double.isNaN(double) method, or your Double's .isNaN() method.

// 1. static method
if (Double.isNaN(doubleValue)) {
    ...
}
// 2. object's method
if (doubleObject.isNaN()) {
    ...
}

Simply doing:

if (var == Double.NaN) {
    ...
}

is not sufficient due to how the IEEE standard for NaN and floating point numbers is defined.

Answer 2

Try Double.isNaN():

Returns true if this Double value is a Not-a-Number (NaN), false otherwise.

Note that [double.isNaN()] will not work, because unboxed doubles do not have methods associated with them.

Answer 3

You might want to consider also checking if a value is finite via Double.isFinite(value). Since Java 8 there is a new method in Double class where you can check at once if a value is not NaN and infinity.

/**
 * Returns {@code true} if the argument is a finite floating-point
 * value; returns {@code false} otherwise (for NaN and infinity
 * arguments).
 *
 * @param d the {@code double} value to be tested
 * @return {@code true} if the argument is a finite
 * floating-point value, {@code false} otherwise.
 * @since 1.8
 */
public static boolean isFinite(double d)

Answer 4

You can check for NaN by using var != var. NaN does not equal NaN.

EDIT: This is probably by far the worst method. It's confusing, terrible for readability, and overall bad practice.

Answer 5

Beginners needs practical examples. so try the following code.

public class Not_a_Number {

public static void main(String[] args) {
    // TODO Auto-generated method stub

    String message = "0.0/0.0 is NaN.\nsimilarly Math.sqrt(-1) is NaN.";        
    String dottedLine = "------------------------------------------------";     

    Double numerator = -2.0;
    Double denominator = -2.0;      
    while (denominator <= 1) {
        Double x = numerator/denominator;           
        Double y = new Double (x);
        boolean z = y.isNaN();
        System.out.println("y =  " + y);
        System.out.println("z =  " + z);
        if (z == true){
            System.out.println(message);                
        }
        else {
            System.out.println("Hi, everyone"); 
        }
        numerator = numerator + 1;
        denominator = denominator +1;
        System.out.println(dottedLine);         
    } // end of while

} // end of main

} // end of class

Answer 6

The below code snippet will help evaluate primitive type holding NaN.

double dbl = Double.NaN; Double.valueOf(dbl).isNaN() ? true : false;