char* from char[] member of structure

Question

I have a structure:

typedef struct {
    LogLevel level;
    char message[255];
} LogMessage;

I then have a function which receives a pointer to a LogMessage structure, and needs to call a function that takes in a char*:

xStatus = xQueueReceive(xQueueHandleGSMSend, &lReceivedData, portMAX_DELAY);

if(xStatus == pdPASS)
{
    logSimpleMessage(&lReceivedData->message, 1);
}

Here is the prototype for the logSimpleMessage function:

void logSimpleMessage(const char * message, int level);

When I attempt to call it with the above code, I am not getting the correct address (or contents) of the message. How do I get a char* that points to the message of lReceivedData?

EDIT: I have attempted to use lReceivedData->message, as suggested, but I am still not getting the correct address or values. Here is a screen cap of the IDE... Am I doing something terribly wrong in the debugger, because it seems as though it should work.

Answer 1

instead of

logSimpleMessage(&lReceivedData->message, 1);

you put so:

logSimpleMessage(lReceivedData->message, 1);

Answer 2

&lReceivedData->message

Produces the address of an array. An array will decay to a pointer when needed, so simply use :

logSimpleMessage(lReceivedData->message, 1);

You cannot truly pass an array to a function, the array will always decay to a pointer to the first element.

Answer 3

You only need to pass lReceivedData->message to the function, remove the &:

logSimpleMessage(lReceivedData->message, 1);

A type of char[] decays to a char* when passed to a function.