Question

I want to create a class that takes two parameters. One should be typed simply as T. The other should be typed as something that extends both T and SomeInterface<T>. When I attempt this with

public class SomeClass<T, S extends SomeInterface<T> & T>

then Java complains with

"The type T is not an interface; it cannot be specified as a bounded parameter"

and if instead I attempt to create an interface for S with

public interface TandSomeInterface<T> extends SomeInterface<T>, T

then Java complains with

"Cannot refer to the type parameter T as a supertype"

Is there any way to do this in Java? I think you can do it in C++...?

Was it helpful?

Solution

You can't create an interface that extends the type parameter T since there's no contract that would guarantee T to be an interface. And of course interface extending a class is not allowed.

OTHER TIPS

this works if you extend an interface as well:

public class SomeClass<T extends I, S extends SomeInterface<T> & I>

but maybe it's not exactly what you want ...

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