How to intercept click on link in UITextView?

Question

Is it possible to perform custom action when user touch autodetected phone link in UITextView. Please do not advice to use UIWebView instead.

And please don't just repeat text from apple classes reference - certainly I've already read it.

Thanks.

Answer 1

Update: From ios10,

- (BOOL)textView:(UITextView *)textView shouldInteractWithURL:(NSURL *)URL inRange:(NSRange)characterRange interaction:(UITextItemInteraction)interaction;

From ios7 and Later UITextView has the delegate method:

- (BOOL)textView:(UITextView *)textView shouldInteractWithURL:(NSURL *)URL inRange:(NSRange)characterRange *NS_DEPRECATED_IOS(7_0, 10_0, "Use textView:shouldInteractWithURL:inRange:forInteractionType: instead");*

to intercept the clicks to links. And this is the best way to do it.

For ios6 and earlier a nice way to do this is to by subclassing UIApplication and overwriting the -(BOOL)openURL:(NSURL *)url

@interface MyApplication : UIApplication {

}

@end

@implementation MyApplication


-(BOOL)openURL:(NSURL *)url{
    if  ([self.delegate openURL:url])
         return YES;
    else
         return [super openURL:url];
}
@end

You will need to implement openURL: in your delegate.

Now, to have the application start with your new subclass of UIApplication, locate the file main.m in your project. In this small file that bootstraps your app, there is usually this line:

int retVal = UIApplicationMain(argc, argv, nil, nil);

The third parameter is the class name for your application. So, replacing this line for:

int retVal = UIApplicationMain(argc, argv, @"MyApplication", nil);

This did the trick for me.

Answer 2

In iOS 7 or Later

You can use the following UITextView delegate Method:

- (BOOL)textView:(UITextView *)textView shouldInteractWithURL:(NSURL *)URL inRange:(NSRange)characterRange

The text view calls this method if the user taps or long-presses the URL link. Implementation of this method is optional. By default, the text view opens the application responsible for handling the URL type and passes it the URL. You can use this method to trigger an alternative action, such as displaying the web content at the URL in a web view within the current application.

Important:

Links in text views are interactive only if the text view is selectable but noneditable. That is, if the value of the UITextView the selectable property is YES and the isEditable property is NO.

Answer 3

For Swift 3

textView.delegate = self

extension MyTextView: UITextViewDelegate 

    func textView(_ textView: UITextView, shouldInteractWith URL: URL, in characterRange: NSRange) -> Bool {

        GCITracking.sharedInstance.track(externalLink: URL)
        return true
    }
}

or if target is >= IOS 10

func textView(_ textView: UITextView, shouldInteractWith URL: URL, in characterRange: NSRange, interaction: UITextItemInteraction) -> Bool

Answer 4

Swift version:

Your standard UITextView setup should look something like this, don't forget the delegate and dataDetectorTypes.

var textView = UITextView(x: 10, y: 10, width: CardWidth - 20, height: placeholderHeight) //This is my custom initializer
textView.text = "dsfadsaf www.google.com"
textView.selectable = true
textView.dataDetectorTypes = UIDataDetectorTypes.Link
textView.delegate = self
addSubview(textView)

After your class ends add this piece:

class myVC: UIViewController {
    //viewdidload and other stuff here
}

extension MainCard: UITextViewDelegate {
    func textView(textView: UITextView, shouldInteractWithURL URL: NSURL, inRange characterRange: NSRange) -> Bool {
        //Do your stuff over here
        var webViewController = SVModalWebViewController(URL: URL)
        view.presentViewController(webViewController, animated: true, completion: nil)
        return false
    }
}

Answer 5

With Swift 5 and iOS 12, you can use one of the three following patterns in order to interact with links in a UITextView.

---

#1. Using UITextView's dataDetectorTypes property.

The simplest way to interact with phone numbers, urls or addresses in a UITextView is to use dataDetectorTypes property. The sample code below shows how to implement it. With this code, when the user taps on the phone number, a UIAlertController pops up.

import UIKit

class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()

        let textView = UITextView()
        textView.text = "Phone number: +33687654321"
        textView.isUserInteractionEnabled = true
        textView.isEditable = false
        textView.isSelectable = true
        textView.dataDetectorTypes = [.phoneNumber]
        textView.isScrollEnabled = false

        textView.translatesAutoresizingMaskIntoConstraints = false
        view.addSubview(textView)
        textView.centerXAnchor.constraint(equalTo: view.centerXAnchor).isActive = true
        textView.centerYAnchor.constraint(equalTo: view.centerYAnchor).isActive = true
        textView.leadingAnchor.constraint(equalTo: view.layoutMarginsGuide.leadingAnchor).isActive = true
    }

}

---

#2. Using UITextViewDelegate's textView(_:shouldInteractWith:in:interaction:) method

If you want to perform some custom action instead of making a UIAlertController pop up when you tap on a phone number while using dataDetectorTypes, you have to make your UIViewController conform to UITextViewDelegate protocol and implement textView(_:shouldInteractWith:in:interaction:). The code below shows how to implement it:

import UIKit

class ViewController: UIViewController, UITextViewDelegate {

    override func viewDidLoad() {
        super.viewDidLoad()

        let textView = UITextView()
        textView.delegate = self
        textView.text = "Phone number: +33687654321"
        textView.isUserInteractionEnabled = true
        textView.isEditable = false
        textView.isSelectable = true
        textView.dataDetectorTypes = [.phoneNumber]
        textView.isScrollEnabled = false

        textView.translatesAutoresizingMaskIntoConstraints = false
        view.addSubview(textView)
        textView.centerXAnchor.constraint(equalTo: view.centerXAnchor).isActive = true
        textView.centerYAnchor.constraint(equalTo: view.centerYAnchor).isActive = true
        textView.leadingAnchor.constraint(equalTo: view.layoutMarginsGuide.leadingAnchor).isActive = true
    }

    func textView(_ textView: UITextView, shouldInteractWith URL: URL, in characterRange: NSRange, interaction: UITextItemInteraction) -> Bool {
        /* perform your own custom actions here */
        print(URL) // prints: "tel:+33687654321"

        return false // return true if you also want UIAlertController to pop up
    }

}

---

#3. Using NSAttributedString and NSAttributedString.Key.link

As an alternative, you can use NSAttributedString and set a URL for its NSAttributedString.Key.link attribute.The sample code below shows a possible implementation of it. With this code, when user taps on the attributed string, a UIAlertController pops up.

import UIKit

class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()

        let attributedString = NSMutableAttributedString(string: "Contact: ")
        let phoneUrl = NSURL(string: "tel:+33687654321")! // "telprompt://+33687654321" also works
        let attributes = [NSAttributedString.Key.link: phoneUrl]
        let phoneAttributedString = NSAttributedString(string: "phone number", attributes: attributes)
        attributedString.append(phoneAttributedString)

        let textView = UITextView()
        textView.attributedText = attributedString
        textView.isUserInteractionEnabled = true
        textView.isEditable = false
        textView.isSelectable = true
        textView.isScrollEnabled = false

        textView.translatesAutoresizingMaskIntoConstraints = false
        view.addSubview(textView)
        textView.centerXAnchor.constraint(equalTo: view.centerXAnchor).isActive = true
        textView.centerYAnchor.constraint(equalTo: view.centerYAnchor).isActive = true
        textView.leadingAnchor.constraint(equalTo: view.layoutMarginsGuide.leadingAnchor).isActive = true
    }

}

Answer 6

I haven't tried that myself but you can try to implement application:handleOpenURL: method in your application delegate - it looks like all openURL request pass through this callback.

Answer 7

Not sure how you would intercept the detected data link, or what type of function you need to run. But you may be able to utilize the didBeginEditing TextField method to run a test/scan through the textfield if you know what your looking for..such as comparing text strings that meet ###-###-#### format, or begin with "www." to grab those fields, but you would need to write a little code to sniff through the textfields string, reconize what you need, and then extract it for your function's use. I don't think this would be that difficult, once you narrowed down exactly what it is that you wanted and then focussed your if() statement filters down to very specific matching pattern of what you needed.

Of couse this implies that the user is going to touch the textbox in order to activate the didBeginEditing(). If that is not the type of user interaction you were looking for you could just use a trigger Timer, that starts on ViewDidAppear() or other based on need and runs through the textfields string, then at the end of you run through the textfield string methods that you built, you just turn the Timer back off.

Answer 8

application:handleOpenURL: is called when another app opens your app by opening a URL with a scheme your app supports. It's not called when your app begins opening a URL.

I think the only way to do what Vladimir wants is to use a UIWebView instead of a UITextView. Make your view controller implement UIWebViewDelegate, set the UIWebView's delegate to the view controller, and in the view controller implement webView:shouldStartLoadWithRequest:navigationType: to open [request URL] in a view instead of quitting your app and opening it in Mobile Safari.

Answer 9

Swift 4:

1) Create the following class (subclassed UITextView):

import Foundation

protocol QuickDetectLinkTextViewDelegate: class {
    func tappedLink()
}

class QuickDetectLinkTextView: UITextView {

    var linkDetectDelegate: QuickDetectLinkTextViewDelegate?

    override init(frame: CGRect, textContainer: NSTextContainer?) {
        super.init(frame: frame, textContainer: textContainer)

    }

    required init?(coder aDecoder: NSCoder) {
         super.init(coder: aDecoder)
    }

    override func hitTest(_ point: CGPoint, with event: UIEvent?) -> UIView? {
        let glyphIndex: Int? = layoutManager.glyphIndex(for: point, in: textContainer, fractionOfDistanceThroughGlyph: nil)
        let index: Int? = layoutManager.characterIndexForGlyph(at: glyphIndex ?? 0)
        if let characterIndex = index {
            if characterIndex < textStorage.length {
                if textStorage.attribute(NSLinkAttributeName, at: characterIndex, effectiveRange: nil) != nil {
                    linkDetectDelegate?.tappedLink()
                    return self
                }
            }
        }

        return nil
    }
}

2) Wherever you set up your textview, do this:

//init, viewDidLoad, etc
textView.linkDetectDelegate = self

//outlet
@IBOutlet weak var textView: QuickDetectLinkTextView!

//change ClassName to your class
extension ClassName: QuickDetectLinkTextViewDelegate {
    func tappedLink() {
        print("Tapped link, do something")
    }
}

If you're using storyboard, make sure your textview looks like this in the right pane identity inspector:

Voila! Now you get the link tap immediately instead of when the URL shouldInteractWith URL method