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# Oracle Age calculation from Date of birth and Today

### Question

I want to calculate the current Age from Date of Birth in my Oracle function.

What I am using is `(Today-Dob)/30/12`, but this is not accurate as some months have 31 days.

I need to get the correct age with the maximum precision. How can I do that?

### Solution

``````SQL> select trunc(months_between(sysdate,dob)/12) year,
2         trunc(mod(months_between(sysdate,dob),12)) month,
4  from (Select to_date('15122000','DDMMYYYY') dob from dual);

YEAR      MONTH        DAY
---------- ---------- ----------
9          5         26

SQL>
``````

### OTHER TIPS

For business logic I usually find a decimal number (in years) is useful:

``````select months_between(TRUNC(sysdate),
to_date('15-Dec-2000','DD-MON-YYYY')
)/12
as age from dual;

AGE
----------
9.48924731
``````

``````SELECT
TRUNC((SYSDATE - TO_DATE(DOB, 'YYYY-MM-DD'))/ 365.25) AS AGE_TODAY FROM DUAL;
``````

This is easy and straight to the point.

And an alternative without using any arithmetic and numbers (although there is nothing wrong with that):

``````SQL> with some_birthdays as
2  ( select date '1968-06-09' d from dual union all
3    select date '1970-06-10' from dual union all
4    select date '1972-06-11' from dual union all
5    select date '1974-12-11' from dual union all
6    select date '1976-09-17' from dual
7  )
8  select trunc(sysdate) today
9       , d birth_date
10       , extract(year from numtoyminterval(months_between(trunc(sysdate),d),'month')) age
11    from some_birthdays
12  /

TODAY               BIRTH_DATE                 AGE
------------------- ------------------- ----------
10-06-2010 00:00:00 09-06-1968 00:00:00         42
10-06-2010 00:00:00 10-06-1970 00:00:00         40
10-06-2010 00:00:00 11-06-1972 00:00:00         37
10-06-2010 00:00:00 11-12-1974 00:00:00         35
10-06-2010 00:00:00 17-09-1976 00:00:00         33

5 rows selected.
``````

``````with some_birthdays as
(
select date '1968-06-09' d from dual union all
select date '1970-06-10' from dual union all
select date '1972-06-11' from dual union all
select date '1974-12-11' from dual union all
select date '1976-09-17' from dual
)
select trunc(sysdate) today
, d birth_date
, floor(months_between(trunc(sysdate),d)/12) age
from some_birthdays;
``````

This seems considerably easier than what anyone else has suggested

``````select sysdate-to_date('30-jul-1977') from dual;
``````

Age (full years) of the Person:

``````SELECT
TRUNC(months_between(sysdate, per.DATE_OF_BIRTH) / 12) AS "Age"
FROM PD_PERSONS per
``````

``````SQL>select to_char(to_date('19-11-2017','dd-mm-yyyy'),'yyyy') -  to_char(to_date('10-07-1986','dd-mm-yyyy'),'yyyy') year,
to_char(to_date('19-11-2017','dd-mm-yyyy'),'mm') -  to_char(to_date('10-07-1986','dd-mm-yyyy'),'mm') month,
to_char(to_date('19-11-2017','dd-mm-yyyy'),'dd') -  to_char(to_date('10-07-1986','dd-mm-yyyy'),'dd') day from dual;

YEAR      MONTH        DAY
---------- ---------- ----------
31          4          9
``````

You can try

``````SELECT ROUND((SYSDATE - TO_DATE('12-MAY-16'))/365.25, 5) AS AGE from DUAL;
``````

You can configure `ROUND` to show as many decimal places as you wish.

Placing the date in decimal format like aforementioned helps with calculations of age groups, etc.

This is just a contrived example. In real world scenarios, you wouldn't be converting strings to date using `TO_DATE`.

However, if you have date of birth in date format, you can subtract two dates safely.

Suppose that you want to have the age (number of years only, a fixed number) of someone born on `June 4, 1996`, execute this command :

``````SELECT TRUNC(TO_NUMBER(SYSDATE - TO_DATE('04-06-1996')) / 365.25) AS AGE FROM DUAL;
``````

### Result : (Executed May 28, 2019)

``````       AGE
----------
22
``````

### Explanation :

• `SYSDATE` : Get system's (OS) actual date.
• `TO_DATE('04-06-1996')` : Convert `VARCHAR` (string) birthdate into `DATE` (SQL type).
• `TO_NUMBER(...)` : Convert a date to `NUMBER` (SQL type)
• Devide per `365.25` : To have a bissextile year every four years (4 * 0.25 = 1 more day).
• `Trunc(...)` : Retrieve the entire part only from a number.

You can try below method,

`SELECT EXTRACT(YEAR FROM APP_SUBMITTED_DATE)-EXTRACT(YEAR FROM BIRTH_DATE) FROM SOME_TABLE;`

It will compare years and give age accordingly.
You can also use `SYSDATE` instead of `APP_SUBMITTED_DATE`.

Regards.

select (SYSDATE-DOB)/365 "Age" from dual