¿Cómo consigo un nombre de archivo único de un diálogo inmueble en la VBA (para MS Access 2007)?

Question

¿Cómo puedo cambiar mi código para obtener el nombre de archivo en lugar del nombre del directorio? openDialog.InitialFilename me da el nombre del directorio.
openDialog.FileName me da el error "Método o miembro de datos no encontrado".

Private Sub btnEditPhoto_Click()
    If (txtImageName > "") Then

        Application.FollowHyperlink txtImageName

    Else
        Dim openDialog As Office.FileDialog

        Set openDialog = Application.FileDialog(msoFileDialogFilePicker)

            openDialog.Filters.Clear
            openDialog.Filters.Add "JPEG Files", "*.jpg"

        Dim pickedFile As Boolean
            pickedFile = openDialog.Show

        If pickedFile Then
                txtImageName.SetFocus
                txtImageName.Text = openDialog.InitialFileName
        End If

    End If

End Sub

Answer 1

¿Quieres:

OpenDialog.SelectedItems.Item(1)

En lugar de:

OpenDialog.InitialFileName

Como usted no ha permitido selección múltiple.

---

Así que:

''Reference Microsoft Office x.x Object Library
Dim openDialog As Office.FileDialog

Set openDialog = Application.FileDialog(msoFileDialogFilePicker)
openDialog.Filters.Clear
openDialog.Filters.Add "JPEG Files", "*.jpg"

If openDialog.Show Then
    ''SelectedItems is not zero based

    ''Do not use .Text property in MS Access except
    ''in special cases, then you will not have to set focus
    ''txtImageName.SetFocus

    txtImageName = openDialog.SelectedItems(1)
End If

Si se utiliza AllowMultiSelect, es necesario iterar a través de SelectedItems

''Reference Microsoft Office x.x Object Library
Dim openDialog As Office.FileDialog
Dim i As Integer

Set openDialog = Application.FileDialog(msoFileDialogFilePicker)
'Use ctl or shift + click to select more than one file
openDialog.AllowMultiSelect = True
openDialog.Filters.Clear
openDialog.Filters.Add "JPEG Files", "*.jpg"

If openDialog.Show Then
    For i = 1 To openDialog.SelectedItems.Count
        Imagelst = Imagelst & ";" & openDialog.SelectedItems(i)
    Next
End If

Answer 2

que necesitaba para seleccionar un archivo de texto ... esto es lo que hice ... funcionó bien.

' Get the File
'----------------------------------------------------------
Dim dialog As Object
Dim pickedfile As Boolean
Dim myfile As String
Set dialog = Application.FileDialog(msoFileDialogFilePicker)
With dialog
    .AllowMultiSelect = False
    .Title = "Please pick the file to convert."
    .Filters.Clear
    .Filters.Add "Text Files", "*.TXT"
    .Filters.Add "All Files", "*.*"
    pickedfile = False
    pickedfile = .Show
    If pickedfile Then
    myfile = .SelectedItems.Item(1)
    End If
End With
'----------------------------------------------------------

Además ... se puede sustituir el tipo de diálogo con el ...

Set dialog = Application.FileDialog(msoFileDialogOpen)

y funcionó igual de bien.

Answer 3

Private Sub Command135_Click()

Dim dialog As Object
Dim pickedfile As Boolean
Dim myfile As String
Set dialog = Application.FileDialog(1)
With dialog
    .AllowMultiSelect = False
    .Title = "Please pick the file to convert."
    .Filters.Clear
    .Filters.Add "Picture Files", "*.Jpg"
    .Filters.Add "All Files", "*.*"
    pickedfile = False
    pickedfile = .Show
    If pickedfile Then
    myfile = .SelectedItems.Item(1)
    End If
End With

Me.Form.Picture = myfile
End Sub


Command_135=Button Name
Me.Form.Picture = "The Control Name"