Possible de faire un `a` lookup_type " par django-filtre URL analyseur?
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21-12-2019 - |
Question
Je suis à l'aide d' django-filtre avec django-repos-cadre et j'essaie d'instancier un filtre qui accepte les listes de numéros pour le filtrage des requêtes définies
class MyFilter(django_filters.FilterSet):
ids = django_filters.NumberFilter(name='id',lookup_type='in')
class Meta:
model = MyModel
fields = ('ids',)
class MyModelViewSet(viewsets.ModelViewSet):
queryset = MyModel.objects.all()
serializer_class = MyModelSerializer
filter_class = MyFilter
Si je passe dans une liste séparée par des virgules des nombres entiers, le filtre est totalement ignoré.
Si je passe dans un seul entier, il obtient grâce à django-filtre dans django validateur de formulaire et se plaint:
'Decimal' object is not iterable
Est-il un moyen de créer un django-objet de filtre qui permet de gérer une liste d'entiers et correctement le filtre vers le bas le queryset?
La solution
Pour le meilleur ou pire, j'ai créé un filtre personnalisé pour cela:
class IntegerListFilter(django_filters.Filter):
def filter(self,qs,value):
if value not in (None,''):
integers = [int(v) for v in value.split(',')]
return qs.filter(**{'%s__%s'%(self.name, self.lookup_type):integers})
return qs
qui est utilisé comme:
class MyFilter(django_filters.FilterSet):
ids = IntegerListFilter(name='id',lookup_type='in')
class Meta:
model = MyModel
fields = ('ids',)
class MyModelViewSet(viewsets.ModelViewSet):
queryset = MyModel.objects.all()
serializer_class = MyModelSerializer
filter_class = MyFilter
Maintenant, mon interface accepte les listes d'entiers délimités par des virgules.
Autres conseils
Je sais que c'est un vieux post, mais il y a maintenant une meilleure solution.Le changement qui fait correcte est affichée ici.
Ils ont ajouté un BaseInFilter
et un BaseRangeFilter
.La documentation est ici.
Grande image, BaseFilter vérifie CSV, puis lorsqu'il est mélangé avec un autre filtre ne fait que ce que vous demandez.Votre code peut maintenant être écrite comme:
class NumberInFilter(filters.BaseInFilter, filters.NumberFilter):
pass
class MyModelViewSet(viewsets.ModelViewSet):
ids = NumberInFilter(name='id', lookup_expr='in')
class Meta:
model = MyModel
fields = ['ids']
Voici une solution complète:
from django_filters import Filter, FilterSet
from rest_framework.filters import DjangoFilterBackend
from rest_framework.viewsets import ModelViewSet
from .models import User
from .serializers import UserSerializer
class ListFilter(Filter):
def filter(self, qs, value):
if not value:
return qs
self.lookup_type = 'in'
values = value.split(',')
return super(ListFilter, self).filter(qs, values)
class UserFilter(FilterSet):
ids = ListFilter(name='id')
class Meta:
model = User
fields = ['ids']
class UserViewSet(viewsets.ModelViewSet):
serializer_class = UserSerializer
queryset = User.objects.all()
filter_backends = (DjangoFilterBackend,)
filter_class = UserFilter
According to a post in the django-filter issues:
from django_filters import Filter
from django_filters.fields import Lookup
class ListFilter(Filter):
def filter(self, qs, value):
return super(ListFilter, self).filter(qs, Lookup(value.split(u","), "in"))
I have personally used this without any issue in my projects, and it works without having to create a per-type filter.
Based on @yndolok answer I have come to a general solution. I think filtering by a list of ids is a very common task and therefore should be included in the FilterBackend:
class ListFilter(django_filters.Filter):
"""Class to filter from list of integers."""
def filter(self, qs, value):
"""Filter function."""
if not value:
return qs
self.lookup_type = 'in'
try:
map(int, value.split(','))
return super(ListFilter, self).filter(qs, value.split(','))
except ValueError:
return super(ListFilter, self).filter(qs, [None])
class FilterBackend(filters.DjangoFilterBackend):
"""A filter backend that includes ListFilter."""
def get_filter_class(self, view, queryset=None):
"""Append ListFilter to AutoFilterSet."""
filter_fields = getattr(view, 'filter_fields', None)
if filter_fields:
class AutoFilterSet(self.default_filter_set):
ids = ListFilter(name='id')
class Meta:
model = queryset.model
fields = list(filter_fields) + ["ids"]
return AutoFilterSet
else:
return super(FilterBackend, self).get_filter_class(view, queryset)
Uptodate solution:
from django_filters import rest_framework as filters
name-->field_name
lookup_type-->lookup_expr
class IntegerListFilter(filters.Filter):
def filter(self,qs,value):
if value not in (None,''):
integers = [int(v) for v in value.split(',')]
return qs.filter(**{'%s__%s'%(self.field_name, self.lookup_expr):integers})
return qs
class MyFilter(filters.FilterSet):
ids = IntegerListFilter(field_name='id',lookup_expr='in')
class Meta:
model = MyModel
fields = ('ids',)
class MyModelViewSet(viewsets.ModelViewSet):
queryset = MyModel.objects.all()
serializer_class = MyModelSerializer
filter_class = MyFilter
As I have answered here DjangoFilterBackend with multiple ids, it is now pretty easy to make a filter that accepts list and validates the contents
For Example:
from django_filters import rest_framework as filters
class NumberInFilter(filters.BaseInFilter, filters.NumberFilter):
pass
class MyFilter(filters.FilterSet):
id_in = NumberInFilter(field_name='id', lookup_expr='in')
class Meta:
model = MyModel
fields = ['id_in', ]
This will accept a list of integers from a get parameter. For example /endpoint/?id_in=1,2,3