HBM2DDL.AUTO를 만들 때 테이블 / 뷰가 존재하지 않는 SQLGRAMEREXCETION을 던지는 이유는 무엇입니까?

StackOverflow https://stackoverflow.com//questions/10661878

문제

나는 최대 절전 모드와 봄 및 서블릿으로 실험 해왔다.자, 나는 갇혀있다.왜 내가이 예외를 얻는거야?hbm2ddl.auto가 생성되도록 설정되면 테이블이 자동으로 만들어질 것입니다.

appicationContext.xml 

<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
    <property name="driverClassName" value="org.apache.derby.jdbc.ClientDriver" />
    <property name="url" value="jdbc:derby://localhost:1527/db;create=true" />
</bean>

<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="dataSource" />
    <property name="packagesToScan" value="org.springpractice.domain" />
    <property name="hibernateProperties">
        <props>
            <prop key="dialect">
                org.hibernate.dialect.DerbyTenSevenDialect</prop>
            <prop key="show_sql">true</prop>
            <prop key="cache.provider_class">
                org.hibernate.cache.NoCacheProvider</prop>
            <prop key="hbm2ddl.auto">create</prop>
        </props>
    </property> 
</bean>
.

userdetails.java 

package org.springpractice.domain;

@Entity
public class UserDetails {

    @Id @GeneratedValue
    protected int id;
    protected String name;
    protected String email;

    // setters/getters ...
}
.

main.java 

@WebServlet("/")
public class Main extends HttpServlet {
    private static final long serialVersionUID = 1L;

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        PrintWriter pw = response.getWriter();
        pw.println("hello from servlet");

        UserDetails user = new UserDetails();
        user.setEmail("bob.smith@gmail.com");
        user.setName("Bob Smith");

        ApplicationContext beanFactory =
            WebApplicationContextUtils
                .getRequiredWebApplicationContext(getServletContext());
        SessionFactory sessionFactory = (SessionFactory)     beanFactory.getBean("sessionFactory");
        Session session = sessionFactory.openSession();
        session.save(user);
        session.close();

    }

}
.

예외 

org.hibernate.exception.SQLGrammarException: Table/View 'USERDETAILS' does not exist.
org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:82)
org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49)
org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125)
org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:110)
org.hibernate.engine.jdbc.internal.proxy.ConnectionProxyHandler.continueInvocation(ConnectionProxyHandler.java:146)
org.hibernate.engine.jdbc.internal.proxy.AbstractProxyHandler.invoke(AbstractProxyHandler.java:81)
$Proxy10.prepareStatement(Unknown Source)
...
.

도움이 되었습니까?

해결책

속성 이름은 최대 절전 모드로 접두어로되어야합니다. 

<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
    <property name="dataSource" ref="dataSource" />
    <property name="packagesToScan" value="org.springpractice.domain" />
    <property name="hibernateProperties">
        <props>
            <prop key="hibernate.dialect">
                org.hibernate.dialect.DerbyTenSevenDialect</prop>
            <prop key="hibernate.show_sql">true</prop>
            <prop key="hibernate.cache.provider_class">
                org.hibernate.cache.NoCacheProvider</prop>
            <prop key="hibernate.hbm2ddl.auto">create</prop>
        </props>
    </property> 
</bean>
.

btw 다음과 같이 속성을 구성하는 더 간단한 방법이 있습니다 

    <property name="hibernateProperties">
        <value>
            hibernate.dialect=org.hibernate.dialect.DerbyTenSevenDialect
            hibernate.show_sql=true
            hibernate.cache.provider_class=org.hibernate.cache.NoCacheProvider
            hibernate.hbm2ddl.auto"=create
        </value>
    </property>
.

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