이 반환 유형이 작동하지 않는 이유는 무엇입니까? (C ++)
-
23-08-2019 - |
문제
반복자 클래스를 사용하려고 할 때
template<class T>
class list
{
public:
class iterator;
};
template<class T>
class list<T>::iterator
{
//stuff
};
연산자 과부하의 반환 유형으로
template<class T>
class list<T>::iterator
{
public:
iterator& operator++();
protected:
list* lstptr;
};
template<class T>
iterator& list<T>::iterator::operator++()
{
(this->lstptr)->current = ((this->lstptr)->current)->next;
return this;
}
이 오류가 발생합니다.
s:\jeffrey_\my_freeware_games\o\resources\container class\container(spec- o)\container_def.h(213) : error C2143: syntax error : missing ';' before '&'
s:\jeffrey_\my_freeware_games\o\resources\container class\container(spec- o)\container_def.h(213) : error C4430: missing type specifier - int assumed. Note: C++ does not support default-int
s:\jeffrey_\my_freeware_games\o\resources\container class\container(spec- o)\container_def.h(213) : error C2065: 'T' : undeclared identifier
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(235) : error C2039: 'Yes' : is not a member of 'vc_attributes'
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(235) : error C2065: 'Yes' : undeclared identifier
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(236) : error C2039: 'No' : is not a member of 'vc_attributes'
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(236) : error C2065: 'No' : undeclared identifier
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(237) : error C2039: 'Maybe' : is not a member of 'vc_attributes'
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(237) : error C2065: 'Maybe' : undeclared identifier
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(240) : error C2039: 'NoAccess' : is not a member of 'vc_attributes'
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(240) : error C2065: 'NoAccess' : undeclared identifier
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(241) : error C2039: 'Read' : is not a member of 'vc_attributes'
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(241) : error C2065: 'Read' : undeclared identifier
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(242) : error C2039: 'Write' : is not a member of 'vc_attributes'
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(242) : error C2065: 'Write' : undeclared identifier
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(243) : error C2039: 'ReadWrite' : is not a member of 'vc_attributes'
c:\program files\microsoft visual studio 9.0\vc\include\codeanalysis\sourceannotations.h(243) : error C2065: 'ReadWrite' : undeclared identifier
c:\program files\microsoft visual studio 9.0\vc\include\crtdefs.h(582) : error C2146: syntax error : missing ';' before identifier 'time_t'
c:\program files\microsoft visual studio 9.0\vc\include\crtdefs.h(2047) : error C2143: syntax error : missing ';' before 'identifier'
c:\program files\microsoft visual studio 9.0\vc\include\crtdefs.h(2047) : warning C4091: 'typedef ' : ignored on left of 'localeinfo_struct' when no variable is declared
c:\program files\microsoft visual studio 9.0\vc\include\crtdefs.h(2047) : fatal error C1075: end of file found before the left brace '{' at 'c:\program files\microsoft visual studio 9.0\vc\include\crtdefs.h(174)' was matched
NB : Container_def.h는 내 목록 및 반복자 클래스의 헤더 파일입니다. souceannotations 또는 crtdef가 무엇인지 전혀 모릅니다.
해결책
iterator
그 시점에서 아직 알려지지 않았습니다. 당신은 그것에 있다고 말해야합니다 list<T>
수업:
template<class T>
typename list<T>::iterator& list<T>::iterator::operator++() {
(this->lstptr)->current = ((this->lstptr)->current)->next;
return *this; // *this here, since this is a pointer only
}
주목하십시오 typename
이후로 필요합니다 list<T>::iterator
템플릿 전문화와 함께 접두사가있는 유형이며, 이에 대해 컴파일러에게 알릴 필요가 있습니다. typename
전에. 생략 typename
, 컴파일러는 유형이 아니라고 가정해야하며 동일한 오류 메시지를 생성해야합니다.
코드를 수업에 바로 넣어서 그 번거 로움을 스스로 안전 할 수 있습니다.
template<class T>
class list<T>::iterator
{
public:
iterator& operator++() {
(this->lstptr)->current = ((this->lstptr)->current)->next;
return *this; // *this here, since this is a pointer only
}
protected:
list* lstptr;
};
제휴하지 않습니다 StackOverflow