주요 0을 표시 한 표시 번호
-
02-07-2019 - |
문제
주어진:
a = 1
b = 10
c = 100
2 자리 미만의 모든 숫자에 대해 주요 0을 표시하려면 어떻게해야합니까?
그건,
01
10
100
해결책
Python 2에서는 할 수 있습니다.
print "%02d" % (1,)
원래 % 처럼 printf
또는 sprintf
.
파이썬 3의 경우+ 동일한 동작을 다음과 같이 달성 할 수 있습니다.
print("{:02d}".format(1))
Python 3.6+의 경우 F- 스트링으로 동일한 동작을 달성 할 수 있습니다.
print(f"{1:02d}")
다른 팁
당신이 사용할 수있는 str.zfill
:
print str(1).zfill(2)
print str(10).zfill(2)
print str(100).zfill(2)
인쇄물:
01
10
100
print('{:02}'.format(1))
print('{:02}'.format(10))
print('{:02}'.format(100))
인쇄물:
01
10
100
아니면 이거:
print '{0:02d}'.format(1)
The Pythonic way to do this:
str(number).rjust(string_width, fill_char)
This way, the original string is returned unchanged if its length is greater than string_width. Example:
a = [1, 10, 100]
for num in a:
print str(num).rjust(2, '0')
Results:
01
10
100
Or another solution.
"{:0>2}".format(number)
Use a format string - http://docs.python.org/lib/typesseq-strings.html
For example:
python -c 'print "%(num)02d" % {"num":5}'
width = 5
num = 3
formatted = (width - len(str(num))) * "0" + str(num)
print formatted
This is how I do it:
str(1).zfill(len(str(total)))
Basically zfill takes the number of leading zeros you want to add, so it's easy to take the biggest number, turn it into a string and get the length, like this:
Python 3.6.5 (default, May 11 2018, 04:00:52) [GCC 8.1.0] on linux Type "help", "copyright", "credits" or "license" for more information. >>> total = 100 >>> print(str(1).zfill(len(str(total)))) 001 >>> total = 1000 >>> print(str(1).zfill(len(str(total)))) 0001 >>> total = 10000 >>> print(str(1).zfill(len(str(total)))) 00001 >>>
Use:
'00'[len(str(i)):] + str(i)
Or with the math
module:
import math
'00'[math.ceil(math.log(i, 10)):] + str(i)
s=1
s="%02d"%s
print(s)
the result will be 01
If dealing with numbers that are either one or two digits:
'0'+str(number)[-2:]
or '0{0}'.format(number)[-2:]
!/usr/bin/env python3
Copyright 2009-2017 BHG http://bw.org/
x = 5
while (x <= 15):
a = str("{:04}".format(x))
print(a)
x = x + 1;