Question

I have find query that looks like this.

$this->paginate('Article', array('Article.status !=' => 'Inactive', 'Article.user_id !=' => $blocked_ids, 'Article.tags LIKE' => "%" . trim($this->params['url']['tag']) . "%"))

where $blocked_ids is an array of ids. It throws an error

SQL Error: 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= ('170')

When I removed != it works fine. No Errors

I appreciate any help.

Was it helpful?

Solution

As @Josh suggested, try using NOT IN. The correct format for CakePHP 1.3.x is:

$this->User->find('all', array(
    'conditions' => array(
        'NOT' => array(
            'User.id' => array(1, 2, 3)
        )
    )
));

Taken from http://cakebaker.42dh.com/2007/04/26/how-to-use-not-in-in-a-condition/

OTHER TIPS

$this->paginate(
                'Article',
                array (
                     'Article.status <>' => 'Inactive', 
                     'Article.user_id !=' => $blocked_ids, 
                     'Article.tags LIKE' => "%" . trim($this->params['url']['tag']) . "%"
                   )
              );

This should be handled when you're getting your data in your model function. You should exclude them by using code like this:

'conditions' => array(
     'Article.status' => 'active',

Try using NOT IN instead [MySQL Reference]:

$this->paginate('Article', array('Article.status !=' => 'Inactive', 'Article.user_id NOT IN' => $blocked_ids, 'Article.tags LIKE' => "%" . trim($this->params['url']['tag']) . "%"))
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