how to return selected data from mysql database in php
Question
I am trying to return all selected data from mysql table. What I want is to return data in an array so that I will display that as json data. I acheived following so far but I do not know how ca I return that mysql data.
public function getHome() {
$result = mysql_query("SELECT * FROM places") or die(mysql_error());
// check for result
$no_of_rows = mysql_num_rows($result);
if ($no_of_rows > 0) {
while($row = mysql_fetch_array($result)) {
$data[] = $row;
}
return $data;
} else {
// user not found
return false;
}
}
here where I am calling this method
if($db->getHome()) {
$data = $db->getHome();
$response['success'] = 1;
$response['uid'] = $data['uid'];
$response['name'] = $data['name'];
$response['profile_photo'] = $data['profile_photo_path'];
$response['places']['place_photo'] = $data['place_photo_path'];
$response['places']['created_at'] = $data['created_at'];
echo json_encode($response);
} else {
echo "bye";
}
here is what it echos
{"tag":"home","success":1,"error":0,"uid":null,"name":null,"profile_photo":null,"places":{"place_photo":null,"created_at":null}}
Solution
You need to define $data as an array first, besides that your code looks fine.
$data = array();
As you are, potentially, returning multiple rows you should be doing something like:
$data = $db->getHome(); // There's no need to call this twice
if($data) {
foreach($data as $place) {
// Do what you need to do with each place here
}
}
Take a look at to see the contents of your $data print_r($data);
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