use url.contains("whatyouwant")
ref : http://docs.oracle.com/javase/7/docs/api/java/lang/String.html
سؤال
I have a string called "URL" which stores the url which comes dynamically. Now I would like to show whether the url from youtube or vimeo or facebook or google.
String URL = "https://www.youtube.com/watch?v=M0jmSsQ5ptw"; // this comes dynamically in my code
if [URL contains youtube word ] [ print "URL from YOUTUBE" ]
if [URL contains facebook word ] [ print "URL from FACEBOOK" ]
if [URL contains google word ] [ print "URL from GOOGLE" ]
if [URL contains vimeo word ] [ print "URL from VIMEo" ]
please help me how to find a word in a url.
المحلول
use url.contains("whatyouwant")
ref : http://docs.oracle.com/javase/7/docs/api/java/lang/String.html
نصائح أخرى
Try split()
String URL = "https://www.youtube.com/watch?v=M0jmSsQ5ptw";
System.out.println("URL from "+URL.split("\\.")[1].toUpperCase());
Output:
URL from YOUTUBE
you already answered your own question.
if [URL contains google word ] [ print "URL from GOOGLE" ]
if(URL.contains("google"))
print("URL from GOOGLE")
url.toLowerCase().contains("dynamic code");
system.out.println(url+" from "+ dynamic code;