Assuming the XML file looks like the one you've described in your previous question:
<Restaurants>
<Restaurant>
<name>test</name>
<location>test</location>
</Restaurant>
<Restaurant>
<name>test2</name>
<location>test2</location>
</Restaurant>
</Restaurants>
Yes, I've added root Restaurants
element to make it a valid XML file.
You can use XML Deserialization to get objects from that XML:
Classes
public class Restaurant
{
[XmlElement(ElementName = "name")]
public string Name { get; set; }
[XmlElement(ElementName = "location")]
public string Location { get; set; }
}
public class Restaurants
{
[XmlElement(ElementName="Restaurant")]
public List<Restaurant> Items { get; set; }
}
Deserialization
var serializer = new XmlSerializer(typeof(Restaurants));
var restaurants = serializer.Deserialize(File.OpenRead("Input.txt"));