You are making this quite complicated.
Just find the end of the string (strlen
). Read from both ends a character at a time and if they do not match then it is not a palindrome. If the indexes become the same or they cross then you are done. It is indeed a palindrome.
I.e
bool Palindrome(char *s) {
int left = 0, right = strlen(s) - 1;
while (left < right) {
if (s[left] != s[right] return false;
++left;
--right;
}
return true;
}
EDIT
Similar vain to construct the reverse
char *Reverse(char *s)
{
char *rev = new char[strlen(s) + 1];
int left = 0, right = strlen(s) - 1;
while (right > -1) {
rev[left] = s[right];
right--;
left++;
}
rev[left] = 0;
// Remember to use delete[]
return rev;
}
EDIT 2
Or
void Reverse(char[] s, int len) {
int left = 0; right = len;
while (right > -1) {
char t = s[left];
s[left] = s[right];
s[right] = t;
left++; right--;
}
}
Then make a copy of the string, reverse it and compare it.