Find the minimum value of a list and print the corresponding index from another list

Question

Say I have some lists, e.g.

list1 = [9.2,6.6,3.1,6.9]
list2 = [1,2,3,4]

I want to find the minimum value of list1 and take that minimum value's index and use it to print out the value from list2 for that corresponding index.

The min(list1) would give me 3.1, with an index of 2, now i want to print list2[2].

Should note that these are not my actual values, they are much more complicated. I just need the general idea.

Answer 1

list1, list2 = [9.2,6.6,3.1,6.9], [1,2,3,4]
print list2[min((j,i) for i, j in enumerate(list1))[1]]
# 3

Explanation:

min((j,i) for i, j in enumerate(list1)) will give the smallest element along with its index. In this case, it will return (3.1, 2). So we take only the second element and get the element corresponding to it from list2.

The other way to do the same would be

print min(zip(list1, list2))[1]
# 3

Answer 2

this should do

print (list2[list1.index(min(list1))])

in long form:

list1 = [9.2,6.6,3.1,6.9]
list2 = [1,2,3,4]
a = min(list1)
b= list1.index(a)  
print (list2[b])

Answer 3

It could be done using index:

list2[list1.index(min(list1))]

Output:

3