NameError: global name 'sock' is not defined

Question

I've defined a socket called sock in my Main.py. From Main.py I import Functions.py, where there's a function (or a method, dunno how they're called in Python) called sendMessage. In sendMessage I need to use the sock I defined in my Main.py. How do I do this? I've tried adding global sock to my function/method, but to no effect.

Main.py

#! /usr/bin/env python

import sys 
import socket 
import string 
import os
import commands
import time
from config import *
from functies import *
from php import *

sock = socket.socket ()
sock.connect ((config['server']['host'], config['server']['poort']))

...

Functions.py

#! /usr/bin/env python

def sendMessage (receiver, message):
    global sock
    sock.send ('PRIVMSG ' + ontvanger + ' :' + message + '\n')

The error

Traceback (most recent call last):
  File "Main.py", line 68, in <module>
    sendMessage (receiver, config['nick'] + ' is here!')
  File "/home/robin/microPy/Functions.py", line 4, in sendMessage
    sock.send ('PRIVMSG ' + receiver + ' :' + message + '\n')
NameError: global name 'sock' is not defined

Answer 1

There are no php-style module-overarching global variables in Python. Instead, let sendMessage take the socket as an argument, like this:

# main.py
import socket
from functions import *

sock = socket.socket ()
sock.connect ((config['server']['host'], config['server']['poort']))
sendMessage (sock, receiver, config['nick'] + ' is here!')

# functions.py ; not .php
def sendMessage(sock, receiver, message):
    sock.send ('PRIVMSG ' + ontvanger + ' :' + message + '\n')

Answer 2

Your functions.py have no idea what sock is. Try passing sock instance as an argument.

def sendMessage (sock, receiver, message):
    sock.send ('PRIVMSG ' + ontvanger + ' :' + message + '\n')