numpy function to set elements of array to a value given a list of indices
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27-10-2019 - |
سؤال
I'm looking for a numpy function that will do the equivalent of:
indices = set([1, 4, 5, 6, 7])
zero = numpy.zeros(10)
for i in indices:
zero[i] = 42
المحلول
You can just give it a list of indices:
indices = [1, 4, 5, 6, 7]
zero = numpy.zeros(10)
zero[indices] = 42
نصائح أخرى
If you have an ndarry:
>>> x = np.zeros((3, 3, 3))
>>> y = [0, 9, 18]
>>> x
array([[[ 0., 0., 0.],
[ 0., 0., 0.],
[ 0., 0., 0.]],
[[ 0., 0., 0.],
[ 0., 0., 0.],
[ 0., 0., 0.]],
[[ 0., 0., 0.],
[ 0., 0., 0.],
[ 0., 0., 0.]]])
>>> np.put(x, y, 1)
>>> x
array([[[ 1., 0., 0.],
[ 0., 0., 0.],
[ 0., 0., 0.]],
[[ 1., 0., 0.],
[ 0., 0., 0.],
[ 0., 0., 0.]],
[[ 1., 0., 0.],
[ 0., 0., 0.],
[ 0., 0., 0.]]])
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