thats a notice error thats warning you about concatenating to a variable that doesn't yet exist.
add this line above your foreach to remove it:
$users = "";
foreach($array_list as $key => $value.....
سؤال
So I have aquired a PHP Script which checks and grabs server information from the servers of the popular game 'Minecraft'. Everything in the script seems to work perfect but I get one error,
Notice: Undefined variable: users in C:\xampp\htdocs\web-root\UNNAMED\share\site\fol\avatarquery.php on line 74
I have no idea why this is happening (I am relatively new to PHP), here's the PHP code;
<?php
//Take the username values from the array & grab the avatars from Minotar.
foreach($array_list as $key => $value){$users .= "<a data-placement=\"top\" rel=\"tooltip\" style=\"display: inline-block;\" title=\"".$value."\">
<img src=\"https://minotar.net/avatar/".$value."/50\" size=\"40\" width=\"40\" height=\"40\" style=\"width: 40px; height: 40px; margin-bottom: 5px; margin-right: 5px; border-radius: 3px;\"/></a>";}
//Display the avatars only when there are players online.
if($data_general['players']['online'] > 0) {
print_r($users);
}
//If no avatars can be shown, display an error.
else {
echo "<div class=\"alert\"> There are no players online at the moment!</div>";
}
?>
Any and all help would be greatly appreciated! Thank you!
Oh and the code <img src="
is line 74.
المحلول
thats a notice error thats warning you about concatenating to a variable that doesn't yet exist.
add this line above your foreach to remove it:
$users = "";
foreach($array_list as $key => $value.....