سؤال
I want to disable the button if specific text has been found in any label.
The following code doesn't run because aTags[i].innerText is not equal to searchText all the time which is wrong because the label has inner text = "a" and the searchText variable have "a" as text - I need it to run in IE
https://stackoverflow.com/questions/23083608
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Russian<html>
<script language="javascript">
$(document).ready(function () {
var aTags = document.getElementsByTagName("label");
var searchText = "a";
var found;
for (var i = 0; i < aTags.length; i++) {
if (aTags[i].innerText == searchText) {
document.getElementById('choose').disabled=true;
break;
}
else
{
alert("failed")
}
}
});
</script>
<label> a </label> <br/>
<label> b </label> <br/>
<label> c </label> <br/>
<input type='button' value='choose' id='choose' />
</html>
المحلول
Seems like there should be easier ways to do that with jQuery
$(function () {
var searchText = "a";
$('#choose').prop('disabled', function() {
return $('label').filter(function(_,el) {
return $.trim( $(el).text() ) === searchText;
}).length > 0;
});
});
نصائح أخرى
The issue is that your label contains " a " (with the spaces), but you're comparing with "a" (no spaces).
If you want to ignore the spaces, you can use jQuery's $.trim(...) to trim the text off the innerText.
But as you're using jQuery, you can dramatically reduce that code:
$(document).ready(function() {
var searchText = "a";
var found = false;
$("label").each(function() {
found = $.trim($(this).text()) === searchText;
if (found) {
return false; // No need to keep looking
}
});
$("#choose").prop("disabled", true);
});
Since you're already using jQuery, you can do what you like with much less complexity. This will work:
(function ($) {
var searchText = "a";
$('label').each(function(){
if ($.trim($(this).text()) === searchText) {
$('#choose').prop('disabled', true);
}
});
})(jQuery);
You have to trim label's text. Try with:
if (aTags[i].innerText.trim() == searchText)
or without trim method:
if (aTags[i].innerText.replace(/^\s+|\s+$/g, '') == searchText)
If you want to match if a substring exists you can try with
aTags[i].innerText.indexOf(searchText) > -1
instead of
aTags[i].innerText == searchText
